Question

我有一个包含StartDate列的表，我想计算两个连续记录之间的时差。

感谢。

@ Mark Byers和@ Yahia，我的请求表为requestId，startdate

requestId    startdate               
1            2011-10-16 13:15:56
2            2011-10-16 13:15:59
3            2011-10-16 13:15:59
4            2011-10-16 13:16:02
5            2011-10-16 13:18:07

我想知道在请求1和＆amp;之间的时差是多少？ 2,2＆amp; 3,3＆amp; 4等等。我知道我需要自己加入桌面，但我的条款没有正确。

Answer 1

要实现您的要求，请尝试以下操作（从OP编辑后更新）：

SELECT A.requestid, A.starttime, (B.starttime - A.starttime) AS timedifference
FROM MyTable A INNER JOIN MyTable B ON B.requestid = (A.requestid + 1)
ORDER BY A.requestid ASC

如果requestid不连续，那么您可以使用

SELECT A.requestid, A.starttime, (B.starttime - A.starttime) AS timedifference
FROM MyTable A CROSS JOIN MyTable B
WHERE B.requestid IN (SELECT MIN (C.requestid) FROM MyTable C WHERE C.requestid > A.requestid)
ORDER BY A.requestid ASC

Answer 2

接受的答案是正确的，但给出了数字的差异。例如，如果我有以下2个时间戳：

2014-06-09 09:48:15
2014-06-09 09:50:11

差异以196为单位。这只是5011 - 4815。为了获得时差，您可以按如下方式修改脚本：

SELECT A.requestid, A.starttime, TIMESTAMPDIFF(MINUTE,A.starttime,B.starttime) AS timedifference 
FROM MyTable A INNER JOIN MyTable B ON B.requestid = (A.requestid + 1) 
ORDER BY A.requestid ASC

Answer 3

SELECT TIMESTAMPDIFF(SECOND, grd.startdate, grd1.startdate) as TD FROM myTable A 
inner join myTable B on A.requestId = B.requestId - 1 and 
A.startdate >= '2019-07-01' order by TD desc

计算两行之间的时差

3 个答案: