Question

我有一个通用接口，它有两种泛型类型。我想装饰所有返回的版本，但由于我在调用EnrichWith时不知道类型，它显然不能编译。我已经尝试使用在上下文中传递的EnrichWith重载，想想也许我可以获取传入的泛型类型并调用Activator.CreateInstance，但是在调试和检查它时，上下文没有任何有用的信息。

这是我到目前为止所拥有的。这是我的通用界面：

public interface IServiceOperation<in TRequest, out TResponse> where TResponse : ServiceResult, new()
{
    TResponse PerformService(TRequest validatedRequest);
}

以下是一个示例实现：

public class SignUpService : IServiceOperation<SignUpRequest, SignUpResult>
{
    private readonly IUserRepository _userRepo;

    public SignUpService(IUserRepository userRepo)
    {
        _userRepo = userRepo;
    }

    public SignUpResult PerformService(SignUpRequest validatedRequest)
    {
        var user = Mapper.Map<User>(validatedRequest);

        user.MarkAsLoggedIn();
        user.ChangePassword(validatedRequest.UnhashedPassword);

        using(var transaction = _userRepo.BeginTransaction())
        {
            _userRepo.Save(user);
            transaction.Commit();
        }

        return new SignUpResult();
    }
}

这是我的装饰者，也接受另一项服务：

public class ValidateServiceDecorator<TRequest, TResponse> : IServiceOperation<TRequest, TResponse> where TResponse : ServiceResult, new()
{
    private readonly IServiceOperation<TRequest, TResponse> _serviceOperation;
    private readonly IValidationService _validationService;

    public ValidateServiceDecorator(IServiceOperation<TRequest, TResponse> serviceOperation,
        IValidationService validationService)
    {
        _serviceOperation = serviceOperation;
        _validationService = validationService;
    }

    public TResponse PerformService(TRequest request)
    {
        var response = new TResponse();
        var validationResult = _validationService.Validate(request);

        if (!validationResult.IsValid)
        {
            response.ValidationErrors = validationResult.ValidationErrors;
            return response;
        }

        return _serviceOperation.PerformService(request);
    }

最后，这是我在容器上走了多远。这显然不能编译，但EnrichWith行显示了我想要实现的目标：

public class StructureMapServiceScanner : Registry
{
    public StructureMapServiceScanner()
    {
        Scan(scanner =>
                {
                    scanner.AssemblyContainingType(typeof (IServiceOperation<,>));
                    scanner.ConnectImplementationsToTypesClosing(typeof (IServiceOperation<,>));
                });

        For(typeof (IServiceOperation<,>))
        .EnrichWith((ioc, original) => new ValidateServiceDecorator(original, ioc.GetInstance<IValidationService>()));
    }
}

只是因为这个问题需要更多的代码，这是我的测试，我试图通过：

[TestClass]
public class StructureMapServiceScannerSpecs
{
    [TestMethod]
    public void Test()
    {
        ObjectFactory.Configure(cfg =>
                                    {
                                        cfg.AddRegistry<StructureMapServiceScanner>();
                                        cfg.For<IUserRepository>().Use(new Mock<IUserRepository>().Object);
                                        cfg.For<IValidationService>().Use(new Mock<IValidationService>().Object);
                                    });

        var service = ObjectFactory.GetInstance<IServiceOperation<SignUpRequest, SignUpResult>>();

        service.ShouldNotBeNull();
        service.ShouldBeType<ValidateServiceDecorator<SignUpRequest, SignUpResult>>();
    }
}

我觉得这应该是简单的，我真的错过了如何使用StructureMap的东西。我可以为Request和Response类型的所有组合创建特定于类型的版本，但显然这是不可取的。那我错过了什么？

Answer 1

最终能够弄明白。我创建了一个RegistrationConvention：

public class ServiceRegistrationConvention : IRegistrationConvention
{
    public void Process(Type type, Registry registry)
    {
        var interfacesImplemented = type.GetInterfaces();

        foreach (var interfaceImplemented in interfacesImplemented)
        {
            if (interfaceImplemented.IsGenericType && interfaceImplemented.GetGenericTypeDefinition() == typeof(IServiceOperation<,>))
            {
                var genericParameters = interfaceImplemented.GetGenericArguments();
                var closedValidatorType = typeof(ValidateServiceDecorator<,>).MakeGenericType(genericParameters);

                registry.For(interfaceImplemented)
                    .EnrichWith((context, original) => Activator.CreateInstance(closedValidatorType, original,
                                                                                context.GetInstance<IValidationService>()));
            }
        }
    }
}

Answer 2

这是一种仍然利用StructureMap的IoC功能的方法，允许将额外的服务轻松注入装饰器。它并不完美，因为它假设您使用的是主容器而不是子容器，但它可能适用于大多数情况。

public class ServiceRegistrationConvention : IRegistrationConvention
{
    public void Process(Type type, Registry registry)
    {
        var handlerInterfaces = (from t in type.GetInterfaces()
                                 where t.IsGenericType &&
                                       t.GetGenericTypeDefinition() == typeof (IHandle<,>)
                                 select t);

        foreach (var handler in handlerInterfaces)
        {
            var decoratorType = typeof (ValidationDecorator<,>).MakeGenericType(handler.GetGenericArguments());

            registry.For(handler)
                .EnrichWith((ctx, orig) => ObjectFactory.With(handler, orig).GetInstance(decoratorType));
        }
    }
}

理想情况下，StructureMap的IContext应该像IContainer一样公开With方法。没有它，对这个问题来说并不是一个很好的解决方案。

使用Structuremap装饰通用接口

2 个答案: