pthread(分段错误)

时间:2011-11-05 04:55:32

标签: c linux unix pthreads

我是韩国人,我不擅长英语,但如果你在那里给我评论 我会很高兴,并会尝试理解它。

我创建了10个线程,并在创建后尝试加入它们并返回值 但是当我加入最后一个帖子时,我遇到了分段错误。

结果就像这样......

Before Thread 1 create
After Thread 1 create
Before Thread 0 create
After Thread 0 create
Before Thread 1 join
After Thread 1 join
Before Thread 0 join
Segmentation Fault(core dumped)

当我创建4个线程时,它就像

Before Thread 3 create
After Thread 3 create
Before Thread 2 create
After Thread 2 create
Before Thread 1 create
After Thread 1 create
Before Thread 0 create
After Thread 0 create
Before Thread 3 join
After Thread 3 join
Before Thread 2 join
After Thread 2 join
Before Thread 1 join
After Thread 1 join
Before Thread 0 join
Segmentation Fault(core dumped)

我似乎无法找到原因。

#include <stdio.h>
#include <stdlib.h>
#include <pthread.h>
#include <unistd.h>

pthread_mutex_t mutex_lock;

struct arg_struct {
        int a;
        int b;
};

void *t_function(void *data) {
        pthread_mutex_lock(&mutex_lock);

        struct arg_struct *arg = (struct arg_struct *)data;
        long int s;

        s = arg->a;

        pthread_mutex_unlock(&mutex_lock);

        return (void **)s;
}

int main()
{
        int i;

        pthread_t p_thread[2];
        int thr_id;
        int status;

        struct arg_struct arg[2];

        for(i = 1; i >= 0; i--) {
                arg[i].a = i;
                arg[i].b = i;
        }

        pthread_mutex_init(&mutex_lock, NULL);

        for(i = 1; i >= 0; i--) {
                printf("Before Thread %d create\n", i);
                thr_id = pthread_create(&p_thread[i],NULL, t_function, (void *)&arg[i]);
                printf("After Thread %d create\n", i);
                usleep(1000);
        }

        int temp[2];

        for(i = 1; i >= 0; i--) {
                printf("Before Thread %d join\n", i);
                pthread_join(p_thread[i], (void**)&status);
                printf("After Thread %d join\n", i);
                temp[i] = status;
        }i

        printf("%d%d", temp[1], temp[0]);

        pthread_mutex_destroy(&mutex_lock);

        return 0;
}

1 个答案:

答案 0 :(得分:9)

    pthread_t p_thread[2];
    struct arg_struct arg[2];
    int temp[2];

这里只为两个元素分配了空间,因此如果你启动2个以上的线程,你将会从数组的末尾运行,并可能导致堆栈崩溃或损坏。

此外:

            pthread_join(p_thread[i], (void**)&status);

statusint,而不是void *;尝试此操作会尝试在void *中存储int。在许多64位平台上,这也会溢出(因为void *将是8个字节,而int是4)。将status设为void *,然后停止尝试抛弃这样的编译器错误。他们出于某种原因是错误的。