以下Python List Comprehension语句可以改为下面的for循环。
>>> [(x,y) for x in range(5) if x % 2 == 0 for y in range(5) if y % 2 == 1]
>>> result = []
>>> for x in range(5):
if x % 2 == 0:
for y in range(5):
if y % 2 == 1:
result.append((x,y))
我很难理解以下两个列表理解表达式 循环(更易于阅读)表达它们的方法是什么?
[(min([row[i] for row in rows]),max([row[i] for row in rows]))
for i in range(len(rows[0]))]
[[random.random()*(ranges[i][1]-ranges[i][0])+ranges[i][0]
for i in range(len(rows[0]))] for j in range(k)]
答案 0 :(得分:3)
使用你的风格:
我相信第一个这样做:
result = []
for col in range(len(rows[0])):
a = rows[0][col]
b = rows[0][col]
for row in rows:
a = min(a, row[col])
b = max(b, row[col])
result.append((a, b))
答案 1 :(得分:1)
以下是展开第一个循环的示例,请参见此处:http://codepad.org/cn0UFPrD
rows = [[1,2,3,4],[3,5,88,9],[4,55,-6,0],[0,34,22,1222]]
t1 = [(min([row[i] for row in rows]),max([row[i] for row in rows])) for i in range(len(rows[0]))]
print(t1)
# Easy loop
t2 = []
for i in range(len(rows[0])):
innerElements = []
for row in rows:
innerElements.append(row[i])
newTuple = ( min(innerElements),max(innerElements) )
t2.append(newTuple)
print(t2)
你可以用同样的方式扩展第二个循环。