Question

好的，我有2个选择语句：

SELECT DISTINCT Email
FROM         dbo.Customers
WHERE     (Email IS NOT NULL) 
AND (Email LIKE '%@%') 
AND (RIGHT(Email, 4) IN ('.net', '.com', '.org')) 
AND (Email NOT LIKE '%@UniformCity.com') 
AND (Email NOT LIKE '%@LifeUniform.com') 
AND (CHARINDEX('.',Email) <> 1)
AND (RIGHT(RTRIM(Email), 1) <> '.') AND (LEFT(LTRIM(Email), 1) <> '@') 
AND (Email not Like '%[`:;_*-,^[^]()+%\/=#-]%' escape '^') order by Email

AND

SELECT  replace(replace(
replace(
replace(EmailOptOut,'"','')
, ',held','')
, ',unsub','')
, ',confirm','') 
as CleanEmail
FROM [LifeMail].[dbo].[EmailOptOuts]

我只想从Customers表中选择电子邮件，而不是在EmailOptOuts表中。什么是实现这一目标的最佳方式？我想过使用游标和循环，但我相信你们专家知道更好的方法。

Answer 1

绕过清理规则只是为了让下面的代码更清晰，你可以这样做：

SELECT c.Email
    FROM dbo.Customers c
    WHERE NOT EXISTS(SELECT NULL
                         FROM [LifeMail].[dbo].[EmailOptOuts] o
                         WHERE c.Email = o.EmailOptOut)

Answer 2

我将这些表放入临时表中，但如果需要，可以组合查询。

SELECT DISTINCT Email
INTO    #tCustomersEmail
FROM    dbo.Customers
WHERE   ( Email IS NOT NULL )
    AND ( Email LIKE '%@%' )
    AND ( RIGHT(Email, 4) IN ( '.net', '.com', '.org' ) )
    AND ( Email NOT LIKE '%@UniformCity.com' )
    AND ( Email NOT LIKE '%@LifeUniform.com' )
    AND ( CHARINDEX('.', Email) <> 1 )
    AND ( RIGHT(RTRIM(Email), 1) <> '.' )
    AND ( LEFT(LTRIM(Email), 1) <> '@' )
    AND ( Email NOT LIKE '%[`:;_*-,^[^]()+%\/=#-]%' ESCAPE '^' )
ORDER BY Email

SELECT  REPLACE(REPLACE(REPLACE(REPLACE(EmailOptOut, '"', ''), ',held', ''),',unsub', ''), ',confirm', '') AS CleanEmail
INTO #tOptOuts
FROM    [LifeMail].[dbo].[EmailOptOuts]

SELECT Email
FROM #tCustomersEmail AS tce
WHERE Email NOT IN (SELECT CleanEmail FROM #tOptOuts AS too)

Answer 3

您还可以执行以下操作：

SELECT Email     
FROM dbo.Customers      
WHERE Email NOT IN 
    ( SELECT Email                          
      FROM [LifeMail].[dbo].[EmailOptOuts]                          
    )

Answer 4

另外一个解决方案（使用LEFT JOIN）：

SELECT Email     
FROM dbo.Customers  c
LEFT JOIN [LifeMail].[dbo].[EmailOptOuts] b ON (b.EmailOptOut = c.Email)
WHERE b.EmailOptOut IS NULL

Answer 5

SELECT qCustomerEmail.Email 
FROM 
    (SELECT DISTINCT Email
    FROM         dbo.Customers
    WHERE     (Email IS NOT NULL) 
    AND (Email LIKE '%@%') 
    AND (RIGHT(Email, 4) IN ('.net', '.com', '.org')) 
    AND (Email NOT LIKE '%@UniformCity.com') 
    AND (Email NOT LIKE '%@LifeUniform.com') 
    AND (CHARINDEX('.',Email) <> 1)
    AND (RIGHT(RTRIM(Email), 1) <> '.') AND (LEFT(LTRIM(Email), 1) <> '@') 
    AND (Email not Like '%[`:;_*-,^[^]()+%\/=#-]%' escape '^')) qCustomerEmail
LEFT JOIN
    (SELECT  replace(replace(
    replace(
    replace(EmailOptOut,'"','')
    , ',held','')
    , ',unsub','')
    , ',confirm','') 
    as CleanEmail
    FROM [LifeMail].[dbo].[EmailOptOuts]) qOptOut
ON qCustomerEmail.Email = qOptOut.CleanEmail
WHERE qOptOut.CleanEmail IS NULL

什么是将表数据与另一表数据进行比较的最佳方法？

5 个答案: