Question

我使用以下代码将表单数据插入到数据库中的单个表中。

function insert_interests($uid, $interests) {
/* first, we'll delete any entries this user already has in the table */
    purge_lookup("jss_users_interests_table", $uid);
/* now create the sql insert query */
    global $db;
    $db->query(create_checkbox_query($interests, "jss_users_interests_table", $uid));
}
/* helper function for insert_interests(). removes all rows in $table with $uid */
function purge_lookup($table, $uid) {
    global $db;
    $db->query("DELETE FROM $table WHERE users_id = '".$db->escape($uid)."'");
}
/* helper function for insert_interests(). generates the actual SQL query */
function create_checkbox_query($arr, $table, $uid) {
    $q = "INSERT INTO $table (users_id, subcategories_id) VALUES";
    foreach ($arr as $check) {
    $q .=  " ( '$uid' , $check )" . ",";
    }
/* remove the last comma and return */  
return substr($q, 0, -1);
}`

在此代码之后，我想使用与另一个表中的其他数据配对的相同表单数据将新记录插入到不同的表中。这是两个表格的结构。

jss_users_interests_table

users_id
subcategories_id

jss_info_requests_table

users_id
PROVIDER_ID
subcategories_id

jss_providers_assignments_table

PROVIDER_ID
subcategories_id

因此，在将数据插入jss_users_interests_table之后我需要做的是将相同的数据与来自 jss_provider_assignment_table 的每个subcategories_id's对应provider_id插入 jss_info_requests_table 。合理？我把它搞砸了，让它变得复杂吗？

任何语法帮助都很棒。谢谢！

Answer 1

这个SQL可能有效。

 INSERT INTO jss_info_requests_table 
 (users_id, provider_id, subcategories_id)
SELECT a.users_id,
 b.provider_id, b.subcategories_id FROM
 jss_users_interests_table a,
 jss_providers_assignments_table b 
 WHERE a.subcategories_id =
 b.subcategories_id AND a.users_id =
 [USERID]

使用php将类似数据插入两个表中

1 个答案: