Question

当我来到正则表达式时，我完全迷失了。我得到了生成的字符串，如：

Your number is (123,456,789)

如何过滤掉123,456,789？

Answer 1

您可以使用此正则表达式来提取包括逗号

在内的数字

\(([\d,]*)\)

第一个被捕获的小组会有你的比赛。代码看起来像这样

String subjectString = "Your number is (123,456,789)";
Pattern regex = Pattern.compile("\\(([\\d,]*)\\)");
Matcher regexMatcher = regex.matcher(subjectString);
if (regexMatcher.find()) {
    String resultString = regexMatcher.group(1);
    System.out.println(resultString);
}

正则表达式的解释

"\\(" +          // Match the character “(” literally
"(" +           // Match the regular expression below and capture its match into backreference number 1
   "[\\d,]" +       // Match a single character present in the list below
                      // A single digit 0..9
                      // The character “,”
      "*" +           // Between zero and unlimited times, as many times as possible, giving back as needed (greedy)
")" +
"\\)"            // Match the character “)” literally

这将让您开始http://www.regular-expressions.info/reference.html

Answer 2

String str="Your number is (123,456,789)";
str = str.replaceAll(".*\\((.*)\\).*","$1");

或者您可以通过以下方式更快地进行替换：

str = str.replaceAll(".*\\(([\\d,]*)\\).*","$1");

Answer 3

试

"\\(([^)]+)\\)"

或

int start = text.indexOf('(')+1;
int end = text.indexOf(')', start);
String num = text.substring(start, end);

Answer 4

private void showHowToUseRegex()
{
    final Pattern MY_PATTERN = Pattern.compile("Your number is \\((\\d+),(\\d+),(\\d+)\\)");
    final Matcher m = MY_PATTERN.matcher("Your number is (123,456,789)");
    if (m.matches()) {
        Log.d("xxx", "0:" + m.group(0));
        Log.d("xxx", "1:" + m.group(1));
        Log.d("xxx", "2:" + m.group(2));
        Log.d("xxx", "3:" + m.group(3));
    }
}

您会看到第一组是整个字符串，接下来的3组是您的数字。

Answer 5

String str = "Your number is (123,456,789)";
str = new String(str.substring(16,str.length()-1));

Java和正则表达式，子串

5 个答案: