我有一个父类测试,子类是子测试。当我调用test-> run()时,我想运行所有子测试。下面的代码不适用于b.c.父类中无法识别子类。
using namespace std;
class test
{
protected:
short verbosity_;
public:
void setVerbosity(short v)
{
if((v==0 || v==1 || v==2))
{
verbosity_ = v;
}
else
{
cout << " Verbosity Level Invalid " << endl;
}
}
void run()
{
natives natives_1; // this does not work
}
};
class natives : public test
{
public:
natives()
{
this->run();
}
void run()
{
testInts<short>();
testInts<int>();
testInts<long>();
testInts<unsigned short>();
testInts<unsigned int>();
testInts<unsigned long>();
}
protected:
template<class T> void testFloats()
{
}
template<class T> void testInts()
{
short passState, bitDepth;
T failMax, pow2 = 1, minValue = 0, maxValue = 0, bitCount = 0, failValue = 0;
const char* a = typeid(T).name();
bool signedType = ((*a == 't') || (*a == 'j') || (*a == 'm'));
while(pow2 > 0)
{
pow2 *= 2;
bitCount++;
}
maxValue = pow2-1;
failValue = pow2;
int native1 = bitCount;
int native2 = sizeof(T)*8;
int native3 = numeric_limits<T>::digits;
if( !signedType )
{
native1++;
native3++;
}
if(verbosity_>=1) cout << endl << "**********\n" << reportType(a) << "\n**********" << endl << endl;
if ((native1 == native2) && (native1 == native3))
{
if(verbosity_>=1)cout << "Correlation:\t\tPass: " << native1 << endl ;
if(verbosity_>=2)
{
cout << "--Algorithm:\t\t" << native1 << endl;
cout << "--Sizeof:\t\t" << native2 << endl;
cout << "--Reported:\t\t" << native3 << endl;
cout << "----Max Value:\t\t" << maxValue << endl;
cout << "----Max+1\t\t" << failValue << endl;
}
else
{
}
}
else
{
cout << "Correlation:\t\tFail" << endl ;
}
}
string reportType(const char* c1)
{
string s1;
switch(*c1)
{
case 't':
s1 = "Unsigned short";
break;
case 'j':
s1 = "Unsigned int";
break;
case 'm':
s1 = "Unsigned long";
break;
case 's':
s1 = "Short";
break;
case 'i':
s1 = "Int";
break;
case 'l':
s1 = "Long";
break;
default:
s1 = "Switch failed";
}
return s1;
}
};
答案 0 :(得分:1)
可能更好的方法是在run
类中创建一个名为test
的纯虚函数,然后子类的测试将实现它,那些将在你运行时运行在子类的实例上调用run
。
例如:
class Test {
public:
virtual void run() = 0;
void setVerbosity(short v) {
if((v==0 || v==1 || v==2))
verbosity_ = v;
else
cout << " Verbosity Level Invalid " << endl;
}
};
class Natives : public Test {
public:
void run() {
// do all the tests....
}
};
然后你可以做
Natives n;
n.run();
当您通过Test*
(或Test&
)执行此操作时,它们仍然可以运行:
Test* t = new Natives;
t->run(); // runs Natives::run
您也可以在这里使用CRTP,但我认为这是不必要的。
答案 1 :(得分:0)
为什么不使用合成器模式
class Test {
std::vector<Test> subTests;
public:
void addSubTest(Test t) {
subTests.add(t);
}
virtual bool doTest() = 0;
void run() {
for(int i=0; i< subTests.size; ++i) {
subTests[i].doTest();
}
this->doTest();
}