Question

我正在尝试查询表格，但我很难搞清楚查询。

这是我的表格（简化）：

Member
ID  | NAME
1   | Frans
2   | Eric
3   | Stephan
4   | Kris

Evenement
ID  | NAME
1   | Picknic
2   | Party
3   | Movie

Evenement
ID_EVENEMENT    | ID_MEMBER 
1               | Kris
1               | Stephan
1               | Eric
2               | Eric
2               | Frans
3               | Frans
3               | Stephan

好的，我想要的查询是：

我想

select
    member_evenement.ID_MEMBER and member_evenement.ID_EVENEMENT
from
    member_evenement
where
    member.ID on member_evenement.ID_MEMBER
where
    member_evenement.ID_MEMBER does not exist
        for each member_evenement.ID_EVENEMENT

分开。

我正在使用sql server 2008 R2

我希望我能够很好地解释我的问题。

如果这些是我的基础表

Member
ID  | NAME
1   | Frans
2   | Eric
3   | Stephan
4   | Kris

Evenement
ID  | NAME
1   | Picknic
2   | Party
3   | Movie

Member_Evenement
ID_EVENEMENT    | ID_MEMBER 
1               | Kris
1               | Stephan
1               | Eric
2               | Eric
2               | Frans
3               | Frans
3               | Stephan

然后我的查询结果应如下所示：

Evenement
ID_EVENEMENT    | ID_MEMBER | MEMBER_NAME   | EVENEMENT_NAME
1               | 1         | Frans         | Picknic
2               | 3         | Stephan       | Party
2               | 4         | Kris          | Party
3               | 2         | Eric          | Movie
3               | 4         | Kris          | Movie

Answer 1

要返回未记录在member_evenement表中的成员和evenement的所有组合，请尝试以下操作：

select e.id id_evenement,
       m.id id_member,
       m.name member_name,
       e.name evenement_name
from member m
cross join evenement e
left join member_evenement me
on e.id = me.id_evenement and m.id = me.id_member
where me.id_evenement is null or me.id_member is null

（这假设id_member实际上是成员的id，而不是样本数据中的名称。）

Answer 2

SELECT e.ID AS ID_EVENEMENT, m.ID AS ID_MEMBER, 
  FROM Evenement e, Member m
EXCEPT
SELECT ID_EVENEMENT, ID_MEMBER 
  FROM member_evenement;

Answer 3

另一种可能性，与Mark Bannister的完全相同的执行计划和onedaywhen的答案如下：

SELECT member.id AS memberid, evenement.id AS evenementid 
FROM member 
CROSS JOIN evenement WHERE
  NOT EXISTS(
    SELECT NULL AS [Empty] 
    FROM member_evenement 
    WHERE member_evenement.memberid = member.id 
    AND member_evenement.evenementid = evenement.id
  )

查询多对多表

3 个答案: