Question

我想要做的是操纵鼠标。对于我自己的目的，它将是一个简单的宏。因此，它会将我的鼠标移动到屏幕上的某个位置，然后点击，就像我按一定间隔点击一样。

Answer 1

这是一个使用非托管函数模拟鼠标点击的代码：

//This is a replacement for Cursor.Position in WinForms
[System.Runtime.InteropServices.DllImport("user32.dll")]
static extern bool SetCursorPos(int x, int y);

[System.Runtime.InteropServices.DllImport("user32.dll")]
public static extern void mouse_event(int dwFlags, int dx, int dy, int cButtons, int dwExtraInfo);

public const int MOUSEEVENTF_LEFTDOWN = 0x02;
public const int MOUSEEVENTF_LEFTUP = 0x04;

//This simulates a left mouse click
public static void LeftMouseClick(int xpos, int ypos)
{
    SetCursorPos(xpos, ypos);
    mouse_event(MOUSEEVENTF_LEFTDOWN, xpos, ypos, 0, 0);
    mouse_event(MOUSEEVENTF_LEFTUP, xpos, ypos, 0, 0);
}

要在特定时间内按住鼠标，您可以Sleep()执行此功能的线程，例如：

mouse_event(MOUSEEVENTF_LEFTDOWN, xpos, ypos, 0, 0);
System.Threading.Thread.Sleep(1000);
mouse_event(MOUSEEVENTF_LEFTUP, xpos, ypos, 0, 0);

上述代码将按住鼠标1秒，除非用户按下释放鼠标按钮。 另外，请确保不要在主UI线程上执行此代码，因为它会导致它挂起。

Answer 2

您可以按XY位置移动。示例如下：

windows.Forms.Cursor.Position = New System.Drawing.Point(Button1.Location.X + Me.Location.X + 50, Button1.Location.Y + Me.Location.Y + 30)

要点击，您可以使用以下代码：

using System.Runtime.InteropServices;

private const UInt32 MOUSEEVENTF_LEFTDOWN = 0x0002;
private const UInt32 MOUSEEVENTF_LEFTUP = 0x0004;
[DllImport("user32.dll")]
    private static extern void mouse_event(uint dwFlags, uint dx, uint dy, uint dwData,             uint dwExtraInf);
private void btnSet_Click(object sender, EventArgs e)
    {
        int x = Convert.ToInt16(txtX.Text);//set x position 
        int y = Convert.ToInt16(txtY.Text);//set y position 
        Cursor.Position = new Point(x, y);
        mouse_event(MOUSEEVENTF_LEFTDOWN, 0, 0, 0, 0);//make left button down
        mouse_event(MOUSEEVENTF_LEFTUP, 0, 0, 0, 0);//make left button up
    }

归功于JOHNYKUTTY

如何在屏幕上的某个位置模拟鼠标点击？

2 个答案: