Question

当我从数据库中删除用户时，我不断收到错误消息，表示目前无法删除用户帐户。我找不到任何突出的sytanx错误，我很确定我的sql查询是正确的。删除用户帐户的表单要求输入用户名，密码，名字和电子邮件，但只检查用户名和密码。我是以错误的方式来做这件事的？

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<!DOCTYPE html>
<html>
    <head>
        <meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
        <title>Deleting Account </title>
    </head>
    <body>
        <?php
                  $db_server = "server";
                  $db_username = "name";
                  $db_password = "pass";

       $con = mysql_connect($db_server, $db_username, $db_password);if (!$con)
                {
                    die('Could not connect: ' . mysql_error());
                }

               $database = "Account_Holder";  

              $er = mysql_select_db($db_username);
        if (!$er) 
        {
         print ("Error - Could not select the database");
         exit;
        }        
            if (isset($_POST['Submit']) && isset($_POST['firstname']) && isset($_POST['password']) && isset($_POST['username'])&& isset($_P0ST['email']))
            {

            //if (isset($_POST['Submit'])
            //{
            $firstname =  $_P0ST['firstname']; 
            $password =  $_POST['password']; 
            $username =  $_P0ST['username']; 
            $email = $_P0ST['email'];

                $query = "DELETE FROM Account_Holder WHERE username ='$username' AND password ='$password'";
                $result = mysql_query($query);
                print("Your account has been deleted. Goodbye."); 
            }
            else
            {
                print("Your account can not be deleted at this time."); 
            }
        ?>
    </body>
</html>

Answer 1

您的查询的数据库名称为“Account_Holder”而不是表名。

$query = "DELETE FROM Account_Holder WHERE username ='$username' AND password ='$password'";

将其更改为适当的表名，然后重试。

Answer 2

在我看来，if语句中的某些内容未按预期设置：

其中一个未在POST中设置：提交，名字，密码，用户名或电子邮件

我会检查您的表单以确保它将方法属性设置为“post”，并且您的表单中包含与之匹配的元素。您也可以在Fiddler，Firebug或Dragonfly等Web调试器中打开它，以便查看POSTed请求，并确保所有这些元素实际上都被发送到服务器。

Answer 3

print_r($_POST);并检查此if语句中的所有值是否来临

 if (isset($_POST['Submit']) && isset($_POST['firstname']) && isset($_POST['password']) && isset($_POST['username'])&& isset($_P0ST['email']))

Answer 4

我假设您在代码中完成了验证，只需要检查

if (isset($_POST['Submit'])) {

   $firstname =  $_POST['firstname']; 
   $password =  $_POST['password']; 
   $username =  $_POST['username']; 
   $email = $_POST['email'];

   $query = "DELETE FROM Account_Holder WHERE username ='$username' AND password ='$password'";
         $result = mysql_query($query);
         print("Your account has been deleted. Goodbye."); 
} else {
     print("error..");
}

从数据库中删除用户

4 个答案: