Question

我试图从ManyToManyField获取数据，但发现运气不好。你能帮帮我吗？这是我的Song App模型。

  class Artist(models.Model):
    name = models.CharField(max_length=100)
    slug = models.SlugField(unique = True,max_length=100,help_text="Suggested value automatically generated from name. Must be unique.")


  class Album(models.Model):
    name = models.CharField(max_length=100)
    slug = models.SlugField(unique = True,max_length=100,help_text="Suggested value automatically generated from name. Must be unique.")
    path = models.CharField(max_length=100,null=True, blank=True)
    language = models.ForeignKey(Category)
    albumid = models.CharField(max_length=100)


  class Song(models.Model):
    title = models.CharField(max_length=100)
    artist = models.ManyToManyField(Artist)
    music = models.ForeignKey(Music)
    album = models.ForeignKey(Album)

这是我的看法。我想用标题打印艺术家。 Titles工作正常。但不是Artist

 def movie_details(request,slug):
    movies = get_object_or_404(Movie,slug=slug)
    # calculating wikipedia directory structer for images
    #image_name = movies.image
    name = movies.title
    album_name = Album.objects.get(name__exact=name)
    album_id = album_name.id
    song_list = Song.objects.filter(album=album_id)
    #image_path = generateWikiImage(image_name)
    #
    return render_to_response('base_movies.html',locals(),
                              context_instance=RequestContext(request)
                              )

我试过像这样的模板。 {{song_list.artist}}并收到此消息<django.db.models.fields.related.ManyRelatedManager object at 0x024CBED0> 感谢

Answer 1

ManyRelatedManager是处理ManyToMany关系的对象。要获取您要查找的对象列表，您需要使用其all()方法。

在这种情况下，您将使用{{song_list.artist.all}}，它将为您提供一个QuerySet，然后您可以在模板中进行迭代。

Answer 2

ManyToManyField包含查询集，因此您不能只在模板中输出它。你应该迭代它。

像这样（song是一些Song实例）

<ul>
{% for artist in song.artist.all %}
    <li>{{ artist.name }}</li>
{% endfor %}
</ul>

试图从ManyToManyField获取数据

2 个答案: