Question

我有一系列的IP地址：

1.48.0.0 - 1.51.255.255

如何获取IP地址列表？

Answer 1

如果我理解正确的话......

start = [1,48,0,0]
end   = [1,51,255,255]

def generate_range(start, end):
    cur = start

    while cur < end:     
        cur[3] = int(cur[3]) + 1

        for pos in range(len(cur)-1, -1, -1):
            if cur[pos] == 255:
                cur[pos] = 0
                cur[pos-1] = int(cur[pos-1]) + 1

        yield '.'.join("{}".format(cur[i]) for i in range(0,len(cur)))

for x in generate_range(start, end):
    print (x)

很难看，但会完成这项工作这将创建一个包含所有可能的ip值的生成器序列。

请注意，这是python 3.0代码，为了获得最佳结果，请使用xrange中的python 2.X

编辑：该算法的最新版本有一个错误，此版本没有

Answer 2

from struct import *
from socket import *

for ip in xrange(unpack('!I',inet_pton(AF_INET,"1.47.0.0"))[0],unpack('!I',inet_pton(AF_INET,"1.51.255.255"))[0]):
    print inet_ntop(AF_INET,pack('!I',ip));

f = unpack('!I',inet_pton(AF_INET,"1.47.0.0"))[0]
l = unpack('!I',inet_pton(AF_INET,"1.51.255.255"))[0]
while f < l:
    print inet_ntop(AF_INET,pack('!I',f));
    f = f + 1

通过这种方式，通过IPv6地址也很容易，但是由于IPv6空间的广泛，我不会推荐它。

Answer 3

我使用简单的嵌套while循环实现了它。如果您发现任何错误，请提示我。

a=1
b=48

while b <= 51:
    c=0
    d=0
    while c <= 255:
        d=0
        while d <= 255:
            print str(a)+"."+str(b)+"."+str(c)+"."+str(d)
            d += 1
        c += 1
    b += 1

Answer 4

您可以将此代码扩展为包含4个字段的IP表单。

现在您可以使用ipRange*

startIP='0.0'
endIP = '10.10'
ipRange = []
for i in range(int(startIP.split('.')[-1]), int(endIP.split('.')[-1])):
    for j in range(int(startIP.split('.')[-2]), int(endIP.split('.')[-2])):
        ipRange.append(str(i)+ ''.join('.') + str(j))

结果是：

$ ipRange
['0.0', '0.1', '0.2', '0.3', '0.4', '0.5', '0.6', '0.7', '0.8', '0.9', '1.0', '1.1', '1.2', '1.3', '1.4', '1.5', '1.6', '1.7', '1.8', '1.9', '2.0', '2.1', '2.2', '2.3', '2.4', '2.5', '2.6', '2.7', '2.8', '2.9', '3.0', '3.1', '3.2', '3.3', '3.4', '3.5', '3.6', '3.7', '3.8', '3.9', '4.0', '4.1', '4.2', '4.3', '4.4', '4.5', '4.6', '4.7', '4.8', '4.9', '5.0', '5.1', '5.2', '5.3', '5.4', '5.5', '5.6', '5.7', '5.8', '5.9', '6.0', '6.1', '6.2', '6.3', '6.4', '6.5', '6.6', '6.7', '6.8', '6.9', '7.0', '7.1', '7.2', '7.3', '7.4', '7.5', '7.6', '7.7', '7.8', '7.9', '8.0', '8.1', '8.2', '8.3', '8.4', '8.5', '8.6', '8.7', '8.8', '8.9', '9.0', '9.1', '9.2', '9.3', '9.4', '9.5', '9.6', '9.7', '9.8', '9.9']

Answer 5

获取给定范围内的所有有效IP地址

我会使用专门为处理IP地址而编写的模块。 netaddr （ pip install netaddr ）提供了一个简单的解决方案。这是一个打印给定范围内所有IP地址的示例（例如1.48.0.0 - 1.51.255.255）：

#!/usr/bin/env python

"""Get a list of IP Addresses in a range (CIDR Notation)."""

import sys  # Using for cleanly exiting program.

try:
    # Pythonic manipulation of IPv4, IPv6, CIDR, EUI and MAC network addresses.
    from netaddr import IPNetwork

except ImportError:
    sys.exit(
        """
        Missing 'netaddr' module, get it here:

        https://pypi.python.org/pypi/netaddr
        """
    )


def get_ips(cidr_string):
    """Returns all IPv4 Addresses in a given CIDR Range
    :param cidr_string: IP Address Range in CIDR notation
    :returns: list of IP Addresses
    :rtype: list
    """

    # Cast to list for simpler manipulation.
    ip_list = list(IPNetwork(cidr_string))

    return ip_list

# Get IPs in Range '1.48.0.0 - 1.51.255.255' (Note the CIDR Notation).
ip_list = get_ips('1.48.0.0/14')

for ip_address in ip_list:

    print ip_address

Answer 6

我这样做（在python3中）：

encode()

如何获取IP地址列表？

6 个答案: