Python:当我按下按钮时,如何使按钮冻结? - Tkinter

时间:2011-12-01 16:58:16

标签: python button tkinter

这是一个记忆游戏,用户选择两个按钮(单元格)。如果单元格后面的两个单词匹配,则单词保持可见,否则单元格将被隐藏,您无法看到它们后面的单词。我想要做的是让一个单元格被冻结,如果它在按下时显示它背后的单词。我想将该函数应用于choice1和choice2,甚至是用户已经找到的对。

我尝试将第16行的self.hidden = not self.hidden更改为

if self.hidden:
    self.hidden = False
else:
    self.hidden = False

但这并不完美。

以下是重要部分:

from tkinter import *
import random

class Cell:
    def __init__(self, word, hidden = True):
        self.word = word
        self.hidden = hidden

    def show_word(self):
        """ Shows the word behind the cell """
        if self.hidden:
            self.hidden = False
        else:
            self.hidden = False
        self.button["text"] = str(self)

        if mem.choice1 is None:
            mem.choice1 = self
        elif mem.choice2 is None:
            mem.choice2 = self
            mem.update_tries()
        else:
            choice1, choice2 = mem.choice1, mem.choice2
            mem.choice1, mem.choice2 = self, None
            self.check(choice1, choice2)

    def check(self, choice1, choice2):
        """ Checks if the chosen words are a pair """
        if choice1.word != choice2.word:
            for cell in (choice1, choice2):
                cell.hidden = True
                cell.button['text'] = str(cell)

    def __str__(self):
        """ Displays or hides the word """
        if self.hidden:
            return "---"
        else:
            return self.word

class Memory(Frame):
    """ GUI application that creates a Memory game """
    def __init__(self, master):
        super(Memory, self).__init__(master)
        self.grid()
        self.create_widgets()
        self.tries = 0
        self.choice1 = None
        self.choice2 = None

1 个答案:

答案 0 :(得分:1)

您可以在不再可点击时禁用该按钮:

cell.button.config(state = DISABLED)