Question

我试图创建一个验证!!

的正则表达式

如果文本只有特殊字符或空格，则应验证false ...

Ex：@＃$ ##

如果最后有一些文字和特殊字符，则应返回true ...

EX：测试!!

如果它是以空格或特殊字符开头的。它应该验证为false。

Ex：@＃Test

如果特殊字符（空格或昏迷除外）介于两者之间。它应该验证为false !!

Ex：te＃$ sT

我道歉，对于这个复杂的正则表达式，我的知识不允许我输入我尝试的任何代码。因为我除了[a-b A-B !@#$%^&*()]

更新

使用Fischermaen的答案进行测试 - ^（\ s | \ w）\ w * \ W * $

sdf SDF！：验证为false

_ __ ：验证为真（在得分下）

sadf，sdfsdf ：验证为false

空格：验证为真

Answer 1

试试这个：

foundMatch = Regex.IsMatch(subjectString, @"^(?!\W*$)(?=[ .\w]\w*\W*$).*$");

我试图弄明白你的意思让我很头疼。你必须学会更好地表达自己。

<强>解释

"
^            # Assert position at the beginning of the string
(?!          # Assert that it is impossible to match the regex below starting at this position (negative lookahead)
   \W        # Match a single character that is a “non-word character”
      *      # Between zero and unlimited times, as many times as possible, giving back as needed (greedy)
   $         # Assert position at the end of the string (or before the line break at the end of the string, if any)
)
(?=          # Assert that the regex below can be matched, starting at this position (positive lookahead)
   [ .\w]    # Match a single character present in the list below
             # One of the characters “ .”
             # A word character (letters, digits, etc.)
   \w        # Match a single character that is a “word character” (letters, digits, etc.)
      *      # Between zero and unlimited times, as many times as possible, giving back as needed (greedy)
   \W        # Match a single character that is a “non-word character”
      *      # Between zero and unlimited times, as many times as possible, giving back as needed (greedy)
   $         # Assert position at the end of the string (or before the line break at the end of the string, if any)
)
.            # Match any single character that is not a line break character
   *         # Between zero and unlimited times, as many times as possible, giving back as needed (greedy)
$            # Assert position at the end of the string (or before the line break at the end of the string, if any)
"

Answer 2

以下是我的建议：

^(\s|\w)\w*\W*$

<强>解释

^(\s|\w) the first character has to be a whitespace or a alphanumeric (including underscore)

\w*      followed by any number of alphanumeric (including underscore)

\W*$     at the end of the string any number of any *except* alphanumeric characters are allowed.

Answer 3

据我所知，你只想接受包含一些字母然后是一些特殊字符的字符串。所以像这样：

[(a-zA-Z)+(\!\@\#\$\%\^\&\*\(\))+]

正则表达式的有效文本

3 个答案: