Question

如何删除子节点的父节点，但保留所有子节点？

XML文件是：

<?xml version='1.0'?>
<products>
<product>
<ItemId>531<ItemId>
<modelNumber>00000</modelNumber>
<categoryPath>
<category><name>Category A</name></category>
<category><name>Category B</name></category>
<category><name>Category C</name></category>
<category><name>Category D</name></category>
<category><name>Category E</name></category>
</categoryPath>
</product>
</products>

基本上，我需要删除categoryPath节点和类别节点，但保留产品节点内的所有名称节点。我的目标是这样的文件：

 <?xml version='1.0'?>
<products>
<product>
<ItemId>531<ItemId>
<modelNumber>00000</modelNumber>
<name>Category A</name>
<name>Category B</name>
 <name>Category C</name>
<name>Category D</name>
<name>Category E</name>
</product>
</products>

是否有PHP内置功能来执行此操作？任何指针都会受到赞赏，我只是不知道从哪里开始，因为有很多子节点。

由于

Answer 1

处理XML数据的一个好方法是使用DOM工具。

一旦你了解它，这很容易。例如：

<?php

// load up your XML
$xml = new DOMDocument;
$xml->load('input.xml');

// Find all elements you want to replace. Since your data is really simple,
// you can do this without much ado. Otherwise you could read up on XPath.
// See http://www.php.net/manual/en/class.domxpath.php
$elements = $xml->getElementsByTagName('category');

// WARNING: $elements is a "live" list -- it's going to reflect the structure
// of the document even as we are modifying it! For this reason, it's
// important to write the loop in a way that makes it work correctly in the
// presence of such "live updates".
while($elements->length) {
    $category = $elements->item(0); 
    $name = $category->firstChild; // implied by the structure of your XML 

    // replace the category with just the name 
    $category->parentNode->replaceChild($name, $category); 
} 

// final result:
$result = $xml->saveXML();

<强> See it in action

PHP domDocument删除子节点的子节点

1 个答案: