Java - JTable - 如何获取排序和排序方向的列？

Question

有什么办法可以让JTable的哪一列被排序？排序方向是什么？

感谢。

Answer 1

使用JTable.getRowSorter()获取RowSorter。

然后拨打getSortKey()。 SortKey会告诉您您想知道的内容。

Answer 2

@Override
public boolean onKeyDown(int keyCode, KeyEvent event) {
    if(keyCode==KeyEvent.KEYCODE_BACK) {
        return false;
    }
    return super.onKeyDown(keyCode, event);
}

使用示例：

 /**
 * Returns an array with the indices of the sorted colummns. The array
 * returned is sorted from high priority to low priority. In case there 
 * are less than 3 sorted columns or there aren't RowSorter the values
 * in the returned array will be -1
 * @param table
 * @return array of length 3 with columns indices order by the highest priority descending. 
 */
public static int[] getTableSortedColumns(JTable table){
    int[] index = new int[]{-1,-1,-1};
    List<? extends SortKey> rowSorter = table.getRowSorter().getSortKeys();
    Iterator<? extends SortKey> it = rowSorter.iterator();
    int i = 0;
    while(it.hasNext()){
        SortKey sortKey = it.next();
        if(sortKey.getSortOrder().compareTo(SortOrder.UNSORTED)!=0 ){
            index[i] = sortKey.getColumn();
            i++;
        }
    }        
    return index;
}

/**
 * Return the sort orientation of a column.
 * @param table
 * @param columnIndex
 * @return int i == ascending, -1 == descending, 0 == unsorted 
 */
public static int getTableSortedOrientation(JTable table, int columnIndex){
    int[] indices = getTableSortedColumns(table);
    int orientation = 0;
    for(int i = 0;i<indices.length;i++){
        if(indices[i] == columnIndex){
            SortOrder so = table.getRowSorter().getSortKeys().get(i).getSortOrder();        
            if(so.compareTo(SortOrder.ASCENDING) == 0){
                orientation = 1;
            }else if(so.compareTo(SortOrder.DESCENDING) == 0){
                orientation = -1;
            }
        }
    }        
    return orientation;
}

Answer 3

• 转到JTable
的API文档
• 使用浏览器文本搜索功能查找“排序”
• 找到JTable.getRowSorter()
• 阅读那里的详细信息。