Question

我有这个问题：

$queryf = "SELECT * FROM classifieds 
WHERE city IN ('$cities') AND state IN ('$states') 
ORDER BY FIELD (city, '$cities'), datetime DESC";

$ cities是5英里范围内的一系列附近城市。与州相同。

基本上，我想搜索具有用户输入信息的用户信息表（如craigslist / classifieds类型表），并计算PER CITY的行数。因此，有可能回应如下：

10 results found within 5 miles:
Dublin, CA (8 records)
Hayward, CA (2 records)

有谁知道我如何跟踪/返回城市相同的行数？

Answer 1

是

MySQL为这种聚合提供了大量功能和关键字。

阅读the documentation for your SELECT statement，特别是在谈到GROUP BY条款时。

Answer 2

GROUP BY和COUNT()应该可以满足您的需求：

$queryf = "SELECT *, count(classifieds.id) AS num_cities FROM classifieds 
WHERE city IN ('$cities') AND state IN ('$states') 
GROUP BY city
ORDER BY FIELD (city, '$cities'), datetime DESC";

Answer 3

尝试使用GROUP BY：

SELECT city, COUNT(1) AS count FROM classifieds 
WHERE city IN ('$cities') AND state IN ('$states') 
GROUP BY city

使用参数计算行数

3 个答案: