在Spring Security 2.06中实现自定义AuthenticationProvider

时间:2011-12-27 22:12:26

标签: java spring spring-security

我正在使用Spring Security来保护Struts2 Web应用程序。由于项目限制,我使用的是Spring Security 2.06。

我的团队构建了一个自定义用户管理API,用于在接收用户名和密码参数后对用户进行身份验证,并返回包含角色列表和其他属性(如电子邮件,名称等)的自定义用户对象。

根据我的理解,典型的Spring Security用例使用默认的UserDetailsS​​ervice来检索UserDetails对象;此对象将包含(除其他外)一个密码字段,框架将使用该字段来验证用户。

在我的情况下,我想让我们的自定义API执行身份验证,然后返回包含角色和其他属性(电子邮件等)的自定义UserDetails对象。

经过一些研究,我发现我可以通过AuthenticationProvider的自定义实现来实现这一点。我也有UserDetailsS​​ervice和UserDetails的自定义实现。

我的问题是我真的不明白我应该在CustomAuthenticationProvider中返回什么。我在这里使用自定义UserDetailsS​​ervice对象吗?甚至需要吗?对不起,我真的很困惑。

CustomAuthenticationProvider:

public class CustomAuthenticationProvider implements AuthenticationProvider {

private Logger logger = Logger.getLogger(CustomAuthenticationProvider.class);

private UserDetailsService userDetailsService; //what am i supposed to do with this?

@Override
public Authentication authenticate(Authentication authentication) throws AuthenticationException {
    UsernamePasswordAuthenticationToken auth = (UsernamePasswordAuthenticationToken) authentication;
    String username = String.valueOf(auth.getPrincipal());
    String password = String.valueOf(auth.getCredentials());

    logger.info("username:" + username);
    logger.info("password:" + password);
    /* what should happen here? */

    return null;  //what do i return?
}

@Override
public boolean supports(Class aClass) {
    return true;  //To indicate that this authenticationprovider can handle the auth request. since there's currently only one way of logging in, always return true
}

public UserDetailsService getUserDetailsService() {
    return userDetailsService;
}

public void setUserDetailsService(UserDetailsService userDetailsService) {
    this.userDetailsService = userDetailsService;
}

}

的applicationContext-security.xml文件:

<beans:bean id="customUserDetailsService" scope="prototype" class="com.test.testconsole.security.CustomUserDetailsService"/>

<beans:bean id="customAuthenticationProvider" class="com.test.testconsole.security.CustomAuthenticationProvider">
    <custom-authentication-provider />
    <beans:property name="userDetailsService" ref="customUserDetailsService" />
</beans:bean>

总结一下,这就是我的需要:

  1. 用户通过网络表单登录
  2. 使用内部用户管理API验证用户
  3. 对于成功通过身份验证的用户,请填写GrantedAuthories等
  4. 返回一个包含角色/权限的用户实体,以及其他属性,如电子邮件,名称等。然后,我应该可以像这样访问此对象..

    //spring security get user name
    Authentication auth = SecurityContextHolder.getContext().getAuthentication();
    userName = auth.getName(); //get logged in username
    logger.info("username: " + userName);
    
    //spring security get user role
    GrantedAuthority[] authorities = auth.getAuthorities();
    userRole = authorities[0].getAuthority();
    logger.info("user role: " + userRole);
    
  5. 我希望这是有道理的。任何帮助或指示将不胜感激!

    谢谢!

    更新

    我认为我取得了一些进展。

    我有一个实现Authentication接口的自定义Authentication对象:

    public class CustomAuthentication implements Authentication {
    
        String name;
        GrantedAuthority[] authorities;
        Object credentials;
        Object details;
        Object principal;
        boolean authenticated;
    
        public CustomAuthentication(String name, GrantedAuthority[] authorities, Object credentials, Object details, Object principal, boolean
                                    authenticated){
            this.name=name;
            this.authorities=authorities;
            this.details=details;
            this.principal=principal;
            this.authenticated=authenticated;
    
        }
        @Override
        public GrantedAuthority[] getAuthorities() {
            return new GrantedAuthority[0];  //To change body of implemented methods use File | Settings | File Templates.
        }
    
        @Override
        public Object getCredentials() {
            return null;  //To change body of implemented methods use File | Settings | File Templates.
        }
    
        @Override
        public Object getDetails() {
            return null;  //To change body of implemented methods use File | Settings | File Templates.
        }
    
        @Override
        public Object getPrincipal() {
            return null;  //To change body of implemented methods use File | Settings | File Templates.
        }
    
        @Override
        public boolean isAuthenticated() {
            return false;  //To change body of implemented methods use File | Settings | File Templates.
        }
    
        @Override
        public void setAuthenticated(boolean isAuthenticated) throws IllegalArgumentException {
            //To change body of implemented methods use File | Settings | File Templates.
        }
    
        @Override
        public String getName() {
            return null;  
        }
    }
    

    并更新了我的CustomerAuthenticationProvider类:

        @Override
        public Authentication authenticate(Authentication authentication) throws AuthenticationException {
            UsernamePasswordAuthenticationToken auth = (UsernamePasswordAuthenticationToken) authentication;
            String username = String.valueOf(auth.getPrincipal());
            String password = String.valueOf(auth.getCredentials());
    
            logger.info("username:" + username);
            logger.info("password:" + password);
    
            //no actual validation done at this time
    
            GrantedAuthority[] authorities = new GrantedAuthorityImpl[1];
            authorities[0] = new GrantedAuthorityImpl("ROLE_USER");
    
            CustomAuthentication customAuthentication = new CustomAuthentication("TestMerchant",authorities,"details",username,password,true);
    
        return customAuthentication;
    
        //return new UsernamePasswordAuthenticationToken(username,password,authorities); 
    }
    

    如果我返回UsernamePasswordAuthenticationToken对象,它会起作用,但如果我尝试返回CustomAuthentication,则会收到以下错误:

    java.lang.ClassCastException: com.test.testconsole.security.CustomAuthentication cannot be cast to org.springframework.security.providers.UsernamePasswordAuthenticationToken
        at com.test.testconsole.security.CustomAuthenticationProvider.authenticate(CustomAuthenticationProvider.java:27)
        at org.springframework.security.providers.ProviderManager.doAuthentication(ProviderManager.java:188)
        at org.springframework.security.AbstractAuthenticationManager.authenticate(AbstractAuthenticationManager.java:46)
        at org.springframework.security.intercept.AbstractSecurityInterceptor.authenticateIfRequired(AbstractSecurityInterceptor.java:319)
        at org.springframework.security.intercept.AbstractSecurityInterceptor.beforeInvocation(AbstractSecurityInterceptor.java:258)
        at org.springframework.security.intercept.web.FilterSecurityInterceptor.invoke(FilterSecurityInterceptor.java:106)
        at org.springframework.security.intercept.web.FilterSecurityInterceptor.doFilter(FilterSecurityInterceptor.java:83)
        at org.springframework.security.util.FilterChainProxy$VirtualFilterChain.doFilter(FilterChainProxy.java:390)
        at org.springframework.security.ui.SessionFixationProtectionFilter.doFilterHttp(SessionFixationProtectionFilter.java:67)
        at org.springframework.security.ui.SpringSecurityFilter.doFilter(SpringSecurityFilter.java:53)
        at org.springframework.security.util.FilterChainProxy$VirtualFilterChain.doFilter(FilterChainProxy.java:390)
        at org.springframework.security.ui.ExceptionTranslationFilter.doFilterHttp(ExceptionTranslationFilter.java:101)
        at org.springframework.security.ui.SpringSecurityFilter.doFilter(SpringSecurityFilter.java:53)
        at org.springframework.security.util.FilterChainProxy$VirtualFilterChain.doFilter(FilterChainProxy.java:390)
        at org.springframework.security.providers.anonymous.AnonymousProcessingFilter.doFilterHttp(AnonymousProcessingFilter.java:105)
        at org.springframework.security.ui.SpringSecurityFilter.doFilter(SpringSecurityFilter.java:53)
        at org.springframework.security.util.FilterChainProxy$VirtualFilterChain.doFilter(FilterChainProxy.java:390)
        at org.springframework.security.ui.rememberme.RememberMeProcessingFilter.doFilterHttp(RememberMeProcessingFilter.java:116)
        at org.springframework.security.ui.SpringSecurityFilter.doFilter(SpringSecurityFilter.java:53)
        at org.springframework.security.util.FilterChainProxy$VirtualFilterChain.doFilter(FilterChainProxy.java:390)
        at org.springframework.security.wrapper.SecurityContextHolderAwareRequestFilter.doFilterHttp(SecurityContextHolderAwareRequestFilter.java:91)
        at org.springframework.security.ui.SpringSecurityFilter.doFilter(SpringSecurityFilter.java:53)
        at org.springframework.security.util.FilterChainProxy$VirtualFilterChain.doFilter(FilterChainProxy.java:390)
        at org.springframework.security.ui.basicauth.BasicProcessingFilter.doFilterHttp(BasicProcessingFilter.java:174)
        at org.springframework.security.ui.SpringSecurityFilter.doFilter(SpringSecurityFilter.java:53)
        at org.springframework.security.util.FilterChainProxy$VirtualFilterChain.doFilter(FilterChainProxy.java:390)
        at org.springframework.security.ui.AbstractProcessingFilter.doFilterHttp(AbstractProcessingFilter.java:278)
        at org.springframework.security.ui.SpringSecurityFilter.doFilter(SpringSecurityFilter.java:53)
        at org.springframework.security.util.FilterChainProxy$VirtualFilterChain.doFilter(FilterChainProxy.java:390)
        at org.springframework.security.ui.logout.LogoutFilter.doFilterHttp(LogoutFilter.java:89)
        at org.springframework.security.ui.SpringSecurityFilter.doFilter(SpringSecurityFilter.java:53)
        at org.springframework.security.util.FilterChainProxy$VirtualFilterChain.doFilter(FilterChainProxy.java:390)
        at org.springframework.security.context.HttpSessionContextIntegrationFilter.doFilterHttp(HttpSessionContextIntegrationFilter.java:235)
        at org.springframework.security.ui.SpringSecurityFilter.doFilter(SpringSecurityFilter.java:53)
        at org.springframework.security.util.FilterChainProxy$VirtualFilterChain.doFilter(FilterChainProxy.java:390)
        at org.springframework.security.util.FilterChainProxy.doFilter(FilterChainProxy.java:175)
        at org.springframework.web.filter.DelegatingFilterProxy.invokeDelegate(DelegatingFilterProxy.java:236)
        at org.springframework.web.filter.DelegatingFilterProxy.doFilter(DelegatingFilterProxy.java:167)
        at org.mortbay.jetty.servlet.ServletHandler$CachedChain.doFilter(ServletHandler.java:1157)
        at org.mortbay.jetty.servlet.ServletHandler.handle(ServletHandler.java:388)
        at org.mortbay.jetty.security.SecurityHandler.handle(SecurityHandler.java:216)
        at org.mortbay.jetty.servlet.SessionHandler.handle(SessionHandler.java:182)
        at org.mortbay.jetty.handler.ContextHandler.handle(ContextHandler.java:765)
        at org.mortbay.jetty.webapp.WebAppContext.handle(WebAppContext.java:418)
        at org.mortbay.jetty.handler.ContextHandlerCollection.handle(ContextHandlerCollection.java:230)
        at org.mortbay.jetty.handler.HandlerCollection.handle(HandlerCollection.java:114)
        at org.mortbay.jetty.handler.HandlerWrapper.handle(HandlerWrapper.java:152)
        at org.mortbay.jetty.Server.handle(Server.java:326)
        at org.mortbay.jetty.HttpConnection.handleRequest(HttpConnection.java:536)
        at org.mortbay.jetty.HttpConnection$RequestHandler.headerComplete(HttpConnection.java:915)
        at org.mortbay.jetty.HttpParser.parseNext(HttpParser.java:539)
        at org.mortbay.jetty.HttpParser.parseAvailable(HttpParser.java:212)
        at org.mortbay.jetty.HttpConnection.handle(HttpConnection.java:405)
        at org.mortbay.io.nio.SelectChannelEndPoint.run(SelectChannelEndPoint.java:409)
        at org.mortbay.thread.QueuedThreadPool$PoolThread.run(QueuedThreadPool.java:582)
    

    这就像某些东西不仅仅是期望任何身份验证对象,而是它的特定实现 - UsernamePasswordAuthenticationToken。这让我觉得我可能会错过另一个自定义组件..也许是一个过滤器?

2 个答案:

答案 0 :(得分:48)

如果您要实施自己的AuthenticationProvider,则不必实施UserDetailsServiceUserDetailsService只提供用于加载用户信息的标准DAO,并且实现框架内的一些其他类以使用它。

通常,要使用用户名和密码进行身份验证,您需要实例化DaoAuthenticationProvider并将其注入UserDetailsService。这可能仍然是你最好的方法。如果您实现自己的提供程序,则您负责确保用户提供了正确的密码等。但是,在某些情况下,这是一种更简单的方法。

回答你的“这里会发生什么?”在您的代码中注释,它将类似于

@Override
public Authentication authenticate(Authentication authentication) throws AuthenticationException {
  UsernamePasswordAuthenticationToken auth = (UsernamePasswordAuthenticationToken) authentication;
  String username = String.valueOf(auth.getPrincipal());
  String password = String.valueOf(auth.getCredentials());

  logger.info("username:" + username);
  logger.info("password:" + password); // Don't log passwords in real app

  // 1. Use the username to load the data for the user, including authorities and password.
  YourUser user = ....

  // 2. Check the passwords match (should use a hashed password here).
  if (!user.getPassword().equals(password)) {
    throw new BadCredentialsException("Bad Credentials");
  }

  // 3. Preferably clear the password in the user object before storing in authentication object
  user.clearPassword();

  // 4. Return an authenticated token, containing user data and authorities  

  return new UsernamePasswordAuthenticationToken(user, null, user.getAuthorities()) ;
}

然后可以使用

访问用户对象
Authentication.getPrincipal()

方法,您可以通过将其附加到自定义用户实现来访问其他属性(电子邮件等)。

如何加载用户数据取决于您。所有Spring Security都在关注AuthenticationProvider界面。

您还应该使用相同的算法存储散列密码并验证提供的密码,而不是简单的相等检查。

答案 1 :(得分:3)

感谢您发布此Luke!

更多脑损伤中救了我。

对于任何关心的人来说,只有我注意到的事情:

我的设置:

  • Grails 2.0.4
  • Groovy 1.8
  • spring-security-core 1.2.7.3
  • spring-security-ui 0.2
  • hibernate 2.0.4

当使用非常赞赏的简化/优雅方法时,Luke建议,不要实现自定义UserDetails(或UserDetailsS​​ervice)对象 - 并且 - 使用您自己的用户对象如果您使用spring security中的“sec”自定义标签(当然是在您的页面中),必须采取额外步骤:

当您实例化一个基本的非自定义UsernamePasswordAuthenticationToken时,如果您希望Spring安全自定义间隙标记起作用,则必须再次传递一个扩展Principal的实例。我做了类似的事情,以尽可能简单(在有用/适当的地方引用我的用户域对象值):

def principalUser = new org.springframework.security.core.userdetails.User(user.username, user.password, user.enabled, !user.accountExpired, !user.passwordExpired,!user.accountLocked, authorities)
def token = new UsernamePasswordAuthenticationToken(principalUser, presentedPassword, authorities)

这应满足grails.plugins.springsecurity.SecurityTagLib.determineSource()中测试的条件,因此,您知道,使用<sec:loggedInUserInfo>的网页实际呈现:

if (principal.metaClass.respondsTo(principal, 'getDomainClass')) {
            return principal.domainClass
}

否则,如果您使用您的用户域对象实例化UsernamePasswordAuthenticationToken(在他的示例中为Luke show),那么安全标记lib方法(determineSource())将最好地执行它的级别并返回 org.codehaus.groovy.grails.commons.DefaultGrailsDomainClass ,当标签寻找用户名成员变量时,你会收到错误:

 Error executing tag <sec:ifLoggedIn>: Error executing tag <sec:loggedInUserInfo>: No such property: username for class: org.codehaus.groovy.grails.commons.DefaultGrailsDomainClass

在我的grails项目中重新实现/子类化spring-security-core插件taglib,没有办法同时使用taglib并使用你的自定义域User类来实例化从你的过滤器传递到你的过滤器的令牌提供商。

然后,另外一行代码是非常的小代价:)