获取推送通知的设备令牌

时间:2012-01-10 04:54:33

标签: ios iphone push-notification apple-push-notifications appdelegate

我正在处理推送通知。我编写了以下用于获取设备令牌的代码。

- (BOOL)application:(UIApplication *)application didFinishLaunchingWithOptions:(NSDictionary *)launchOptions {    
    // Override point for customization after application launch.

    // Add the view controller's view to the window and display.
    [self.window addSubview:viewController.view];
    [self.window makeKeyAndVisible];

    NSLog(@"Registering for push notifications...");    
    [[UIApplication sharedApplication] registerForRemoteNotificationTypes:
     (UIRemoteNotificationTypeSound | UIRemoteNotificationTypeAlert)];

    return YES;
}

- (void)application:(UIApplication *)app didRegisterForRemoteNotificationsWithDeviceToken:(NSData *)deviceToken { 
    NSString *str = [NSString stringWithFormat:@"Device Token=%@",deviceToken];
    NSLog(@"This is device token%@", deviceToken);
}

- (void)application:(UIApplication *)app didFailToRegisterForRemoteNotificationsWithError:(NSError *)err { 
    NSString *str = [NSString stringWithFormat: @"Error: %@", err];
    NSLog(@"Error %@",err);    
}

我能够在设备上成功运行应用程序但无法在控制台上获取设备ID。

我对认证和配置文件没有任何问题。

16 个答案:

答案 0 :(得分:127)

您必须使用以下代码来获取设备令牌: -

目标C

- (void)application:(UIApplication *)app didRegisterForRemoteNotificationsWithDeviceToken:(NSData *)deviceToken 
{
    NSString *token = [[deviceToken description] stringByTrimmingCharactersInSet: [NSCharacterSet characterSetWithCharactersInString:@"<>"]];
    token = [token stringByReplacingOccurrencesOfString:@" " withString:@""];
    NSLog(@"content---%@", token);
} 

Swift 3.0

func application(_ application: UIApplication, didRegisterForRemoteNotificationsWithDeviceToken deviceToken: Data)
{
    let   tokenString = deviceToken.reduce("", {$0 + String(format: "%02X",    $1)})
    // kDeviceToken=tokenString
    print("deviceToken: \(tokenString)")
}

答案 1 :(得分:14)

要获取令牌设备,您可以执行一些步骤

1)为开发人员认证和分发认证启用APNS(Apple推送通知服务),然后重新下载这两个文件。

2)重新下载Developer Provisioning和Distribute Provisioning文件。

3)在Xcode界面中:设置PROJECT和TARGETS的配置并进行两次文件配置下载。

4)最后,您需要在AppDelegate文件中添加以下代码以获取令牌设备  (注意:在真实设备中运行应用程序)。

- (BOOL)application:(UIApplication *)application didFinishLaunchingWithOptions:(NSDictionary *)launchOptions {    
     [self.window addSubview:viewController.view];
     [self.window makeKeyAndVisible];

     NSLog(@"Registering for push notifications...");    
     [[UIApplication sharedApplication] registerForRemoteNotificationTypes:
 (UIRemoteNotificationTypeSound | UIRemoteNotificationTypeAlert)];
     return YES;
}

- (void)application:(UIApplication *)app didRegisterForRemoteNotificationsWithDeviceToken:(NSData *)deviceToken { 
     NSString *str = [NSString stringWithFormat:@"Device Token=%@",deviceToken];
     NSLog(@"%@", str);
}

- (void)application:(UIApplication *)app didFailToRegisterForRemoteNotificationsWithError:(NSError *)err { 
     NSString *str = [NSString stringWithFormat: @"Error: %@", err];
     NSLog(@"%@",str);
}

答案 2 :(得分:8)

以下代码用于检索设备令牌。

    // Prepare the Device Token for Registration (remove spaces and < >)
    NSString *devToken = [[[[deviceToken description] 
                            stringByReplacingOccurrencesOfString:@"<"withString:@""] 
                           stringByReplacingOccurrencesOfString:@">" withString:@""] 
                          stringByReplacingOccurrencesOfString: @" " withString: @""];


    NSString *str = [NSString 
                     stringWithFormat:@"Device Token=%@",devToken];
    UIAlertView *alertCtr = [[[UIAlertView alloc] initWithTitle:@"Token is " message:devToken delegate:self cancelButtonTitle:nil otherButtonTitles: nil] autorelease];
    [alertCtr show];
    NSLog(@"device token - %@",str);

答案 3 :(得分:6)

Wasif的答案的Swift版本:

Swift 2.x

var token = deviceToken.description.stringByTrimmingCharactersInSet(NSCharacterSet(charactersInString: "<>"))
token = token.stringByReplacingOccurrencesOfString(" ", withString: "")
print("Token is \(token)")

Swift 3的更新

let deviceTokenString = deviceToken.map { String(format: "%02.2hhx", $0) }.joined()

答案 4 :(得分:4)

如果您仍未获得设备令牌,请尝试输入以下代码,以便注册您的设备以进行推送通知。

它也适用于ios8或更高版本。

#if __IPHONE_OS_VERSION_MAX_ALLOWED >= 80000

    if ([UIApplication respondsToSelector:@selector(registerUserNotificationSettings:)]) {
        UIUserNotificationSettings *settings = [UIUserNotificationSettings settingsForTypes:UIUserNotificationTypeBadge|UIUserNotificationTypeAlert|UIUserNotificationTypeSound
                                                                                 categories:nil];
        [[UIApplication sharedApplication] registerUserNotificationSettings:settings];
        [[UIApplication sharedApplication] registerForRemoteNotifications];
    } else {
        [[UIApplication sharedApplication] registerForRemoteNotificationTypes:
         UIRemoteNotificationTypeBadge |
         UIRemoteNotificationTypeAlert |
         UIRemoteNotificationTypeSound];

    }
#else
    [[UIApplication sharedApplication] registerForRemoteNotificationTypes:
     UIRemoteNotificationTypeBadge |
     UIRemoteNotificationTypeAlert |
     UIRemoteNotificationTypeSound];

#endif

答案 5 :(得分:4)

使用description就是许多答案,wrong approachconsumer property-即使您可以使用它,它也会在iOS 13以上的版本中失效。

相反,您应确保使用实际的二进制数据,而不仅仅是对其的描述。 Andrey Gagan很好地解决了Objective C解决方案,但是幸运的是,它变得更加简单:

Swift 4.2 可在 iOS 13 +

中使用
// credit to NSHipster (see link above)
// format specifier produces a zero-padded, 2-digit hexadecimal representation
let deviceTokenString = deviceToken.map { String(format: "%02x", $0) }.joined()

答案 6 :(得分:3)

在您的Appdelegate中,使用didRegisterForRemoteNotificationsWithDeviceToken方法:

NSString *deviceTokenString = deviceToken.description;
deviceTokenString = [deviceTokenString stringByReplacingOccurrencesOfString:@"[< >]" withString:@"" options:NSRegularExpressionSearch range:NSMakeRange(0, deviceTokenString.length)];
NSLog(deviceTokenString.description);

答案 7 :(得分:2)

从iOS 13开始,Apple更改了[deviceToken description]输出。现在就像这样的{length=32,bytes=0x0b8823aec3460e1724e795cba45d22e8...af8c09f971d0dabc},它对于设备令牌来说是不正确的。

我建议使用以下代码片段解决问题:

+ (NSString *)stringFromDeviceToken:(NSData *)deviceToken {
    NSUInteger length = deviceToken.length;
    if (length == 0) {
        return nil;
    }
    const unsigned char *buffer = deviceToken.bytes;
    NSMutableString *hexString  = [NSMutableString stringWithCapacity:(length * 2)];
    for (int i = 0; i < length; ++i) {
        [hexString appendFormat:@"%02x", buffer[i]];
    }
    return [hexString copy];
}

它适用于iOS13及更低版本。

答案 8 :(得分:2)

iOS 13以上版本的目标C ,由Wasif Saood的答案提供

将以下代码复制并粘贴到AppDelegate.m中以打印设备APN令牌。

set-current-plot "Distribution"
plot [P_distribution] of turtles
set-plot-x-range 0 (max [b] of turtles)

答案 9 :(得分:1)

在构建设置中设置代码签名配置文件如果您有APN启用证书,那么您肯定会获得令牌ID。并删除

配置文件:自动

并设置为

配置文件:您的配置文件证书。

答案 10 :(得分:0)

在Swift 3中获取设备令牌

func application(_ application: UIApplication, didRegisterForRemoteNotificationsWithDeviceToken deviceToken: Data) {

    let deviceTokenString = deviceToken.reduce("", {$0 + String(format: "%02X", $1)})

    print("Device token: \(deviceTokenString)")

}

答案 11 :(得分:0)

在swift 3中获取设备令牌

[exec]
-Dorg.eclipse.jetty.util.log.class?=org.eclipse.jetty.util.log.Slf4jLog

答案 12 :(得分:0)

为了让设备令牌使用以下代码,您只能使用物理设备获取设备令牌。如果您必须在使用模拟器时发送设备令牌,则可以使用以下条件。

  if(!(TARGET_IPHONE_SIMULATOR))
    {
        [infoDict setValue:[[NSUserDefaults standardUserDefaults] valueForKey:@"DeviceToken"] forKey:@"device_id"];
    }
    else
    {
        [infoDict setValue:@"e79c2b66222a956ce04625b22e3cad3a63e91f34b1a21213a458fadb2b459385" forKey:@"device_id"];
    }



- (void)application:(UIApplication*)application didRegisterForRemoteNotificationsWithDeviceToken:(NSData*)deviceToken
{
    NSLog(@"My token is: %@", deviceToken);
    NSString * deviceTokenString = [[[[deviceToken description] stringByReplacingOccurrencesOfString: @"<" withString: @""] stringByReplacingOccurrencesOfString: @">" withString: @""]   stringByReplacingOccurrencesOfString: @" " withString: @""];
    NSLog(@"the generated device token string is : %@",deviceTokenString);
    [[NSUserDefaults standardUserDefaults] setObject:deviceTokenString forKey:@"DeviceToken"];
}

答案 13 :(得分:0)

快捷键4 这对我有用:

第1步进入目标,点击添加功能,然后选择推送通知

在AppDelegate.swift中的

步骤2 中添加以下代码:

func application(_ application: UIApplication, didFinishLaunchingWithOptions launchOptions: [UIApplication.LaunchOptionsKey: Any]?) -> Bool {
     
        UNUserNotificationCenter.current().requestAuthorization(options: [.alert,.sound]) { (didAllow, error) in
            
        }
        UIApplication.shared.registerForRemoteNotifications()
        
        return true
    }
    
    //Get device token
    func application(_ application: UIApplication, didRegisterForRemoteNotificationsWithDeviceToken deviceToken: Data)
    {
        let tokenString = deviceToken.reduce("", {$0 + String(format: "%02X", $1)})
        
        print("The token: \(tokenString)")
    }

答案 14 :(得分:0)

对于 Objective-C

iOS 13 推送令牌有一些变化

- (void)application:(UIApplication *)application didRegisterForRemoteNotificationsWithDeviceToken:(NSData *)deviceToken {
NSString *token = @"";
        if (@available(iOS 13, *)) {
        NSUInteger length = deviceToken.length;
        if (length == 0) {
            token = @"";
        }
        const unsigned char *buffer = deviceToken.bytes;
        NSMutableString *actualToken  = [NSMutableString stringWithCapacity:(length * 2)];
        for (int i = 0; i < length; ++i) {
            [actualToken appendFormat:@"%02x", buffer[i]];
        }
        token = [actualToken copy];
        } else {
            token = [[deviceToken description] stringByTrimmingCharactersInSet: [NSCharacterSet characterSetWithCharactersInString:@"<>"]];
                token = [token stringByReplacingOccurrencesOfString:@" " withString:@""];
        }
        NSLog(@"My token is: %@", token);
}

答案 15 :(得分:-1)

func application(_ application: UIApplication, didRegisterForRemoteNotificationsWithDeviceToken deviceToken: Data) {

    let tokenParts = deviceToken.map { data -> String in
        return String(format: "%02.2hhx", data)
        }
    let token = tokenParts.joined()

    print("Token\(token)")
}