Question

可能重复：
Is there an easy way to parse a (lambda expression) string into an Action delegate?

我想将lambda表达式存储为配置文件中的字符串，并在运行时将这些字符串动态加载到C＃中的lambda表达式中。我的目标是配置和注入规则。任何可用于从字符串创建lambda表达式的实用程序？

对于同一目标，还有其他轻量级解决方案吗？

Answer 1

如果您提前知道表达式的类型，那么您可以将它们编译为类的一部分，然后将它们从生成的程序集中拉回来。

这是一个示例（使用带有字符串并返回bool的表达式）并运行生成的规则。

c：\ temp \ rules.txt的内容为：

file => file.Length == 0
file => System.IO.Path.GetExtension(file) == ".txt"
file => file == null

然后得到的结果是：

Rules found in file:
file => file.Length == 0,
file => System.IO.Path.GetExtension(file) == ".txt",
file => file == null,

Checking rule file => (file.Length == 0) against input c:\temp\rules.txt: False
Checking rule file => (GetExtension(file) == ".txt") against input c:\temp\rules.txt: True
Checking rule file => (file == null) against input c:\temp\rules.txt: False

来源：

using System;
using System.Xml.Linq;
using System.Linq;
using System.IO;
using Microsoft.CSharp;
using System.CodeDom.Compiler;
using System.Reflection;
using System.Linq.Expressions;

class Program
{
    private const string classTemplate = @"
            using System;
            using System.Linq.Expressions;

            public static class RulesConfiguration
            {{
                private static Expression<Func<string, bool>>[] rules = new Expression<Func<string, bool>>[]
                {{
                    {0}
                }};

                public static Expression<Func<string, bool>>[] Rules {{ get {{ return rules; }} }}
            }}
        ";

    static void Main(string[] args)
    {
        var filePath = @"c:\temp\rules.txt";
        var fileContents = File.ReadAllLines(filePath);

        // add commas to the expressions so they can compile as part of the array
        var joined = String.Join("," + Environment.NewLine, fileContents);

        Console.WriteLine("Rules found in file: \n{0}", joined);

        var classSource = String.Format(classTemplate, joined);

        var assembly = CompileAssembly(classSource);

        var rules = GetExpressionsFromAssembly(assembly);

        foreach (var rule in rules)
        {
            var compiledToFunc = rule.Compile();
            Console.WriteLine("Checking rule {0} against input {1}: {2}", rule, filePath, compiledToFunc(filePath));
        }
    }

    static Expression<Func<string, bool>>[] GetExpressionsFromAssembly(Assembly assembly)
    {
        var type = assembly.GetTypes().Single();
        var property = type.GetProperties().Single();
        var propertyValue = property.GetValue(null, null);
        return propertyValue as Expression<Func<string, bool>>[];
    }

    static Assembly CompileAssembly(string source)
    {
        var compilerParameters = new CompilerParameters()
        {
            GenerateExecutable = false,
            GenerateInMemory = true,
            ReferencedAssemblies =
            {
                "System.Core.dll" // needed for linq + expressions to compile
            },
        };
        var compileProvider = new CSharpCodeProvider();
        var results = compileProvider.CompileAssemblyFromSource(compilerParameters, source);
        if (results.Errors.HasErrors)
        {
            Console.Error.WriteLine("{0} errors during compilation of rules", results.Errors.Count);
            foreach (CompilerError error in results.Errors)
            {
                Console.Error.WriteLine(error.ErrorText);
            }
            throw new InvalidOperationException("Broken rules configuration, please fix");
        }
        var assembly = results.CompiledAssembly;
        return assembly;
    }
}

Answer 2

看看Dynamic Linq。这是一个古老的帖子，但总是很有用。

从字符串创建lambda表达式

2 个答案: