Android - 设置logcat消息的最大长度

时间:2012-01-17 01:31:37

标签: android logging

默认情况下,似乎logcat会截断它认为“太长”的任何日志消息。这在Eclipse内部和使用adb -d logcat在命令行上运行logcat时都会发生,并且会截断一些重要的调试消息。

有没有办法增加logcat支持的最大字符串长度,以使其停止截断调试信息? official documentation意味着可能没有,但是logcat可能支持那里没有提到的一些其他选项?

13 个答案:

答案 0 :(得分:84)

好的,有趣的。我很失望地看到答案是“你无法真正扩展它”。我最初的想法是打破它,所以我可以查看整个事情,所以我在这里与大家分享我是如何做到的(不是它有什么特别的,也不是接近效率,但它可以在紧要关头完成工作):

if (sb.length() > 4000) {
    Log.v(TAG, "sb.length = " + sb.length());
    int chunkCount = sb.length() / 4000;     // integer division
    for (int i = 0; i <= chunkCount; i++) {
        int max = 4000 * (i + 1);
        if (max >= sb.length()) {
            Log.v(TAG, "chunk " + i + " of " + chunkCount + ":" + sb.substring(4000 * i));
        } else {
            Log.v(TAG, "chunk " + i + " of " + chunkCount + ":" + sb.substring(4000 * i, max));
        }
    }
} else {
    Log.v(TAG, sb.toString());
}

编辑显示最后一个字符串!

答案 1 :(得分:47)

递归地将它分成几部分。

public static void largeLog(String tag, String content) {
   if (content.length() > 4000) {
       Log.d(tag, content.substring(0, 4000));
       largeLog(tag, content.substring(4000));
   } else {
       Log.d(tag, content);
   }
}

答案 2 :(得分:36)

logcat中有一个固定大小的缓冲区用于二进制日志(/dev/log/events),此限制为1024字节。 对于非二进制日志,还有一个限制:

#define LOGGER_ENTRY_MAX_LEN        (4*1024)
#define LOGGER_ENTRY_MAX_PAYLOAD (LOGGER_ENTRY_MAX_LEN - sizeof(struct logger_entry))

因此,二进制和非二进制日志的实际消息大小约为4076字节。 内核记录器接口强加了LOGGER_ENTRY_MAX_PAYLOAD限制。

liblog源(由logcat使用)也说:

  
      
  • 内核日志驱动程序可能已截断该消息。
  •   

我建议您使用不使用logcat二进制文件的nxlog工具,但由于内核的限制,我怀疑它会解决您的问题。不过,它可能值得一试。 (免责声明:我是作者。)

答案 3 :(得分:10)

for( String line : logMesg.split("\n") ) {
    Log.d( TAG, line );
}

答案 4 :(得分:4)

这是我使用的代码 - 它会截断4000的限制线,同时也会在新线而不是线的中间断线。使更容易阅读的日志文件。

用法:

Logger.debugEntire("....");

实现:

package ...;

import android.util.Log;

import java.util.Arrays;

public class Logger {

    private static final String LOG_TAG = "MyRockingApp";

    /** @see <a href="http://stackoverflow.com/a/8899735" /> */
    private static final int ENTRY_MAX_LEN = 4000;

    /**
     * @param args If the last argument is an exception than it prints out the stack trace, and there should be no {}
     *             or %s placeholder for it.
     */
    public static void d(String message, Object... args) {
        log(Log.DEBUG, false, message, args);
    }

    /**
     * Display the entire message, showing multiple lines if there are over 4000 characters rather than truncating it.
     */
    public static void debugEntire(String message, Object... args) {
        log(Log.DEBUG, true, message, args);
    }

    public static void i(String message, Object... args) {
        log(Log.INFO, false, message, args);
    }

    public static void w(String message, Object... args) {
        log(Log.WARN, false, message, args);
    }

    public static void e(String message, Object... args) {
        log(Log.ERROR, false, message, args);
    }

    private static void log(int priority, boolean ignoreLimit, String message, Object... args) {
        String print;
        if (args != null && args.length > 0 && args[args.length-1] instanceof Throwable) {
            Object[] truncated = Arrays.copyOf(args, args.length -1);
            Throwable ex = (Throwable) args[args.length-1];
            print = formatMessage(message, truncated) + '\n' + android.util.Log.getStackTraceString(ex);
        } else {
            print = formatMessage(message, args);
        }
        if (ignoreLimit) {
            while (!print.isEmpty()) {
                int lastNewLine = print.lastIndexOf('\n', ENTRY_MAX_LEN);
                int nextEnd = lastNewLine != -1 ? lastNewLine : Math.min(ENTRY_MAX_LEN, print.length());
                String next = print.substring(0, nextEnd /*exclusive*/);
                android.util.Log.println(priority, LOG_TAG, next);
                if (lastNewLine != -1) {
                    // Don't print out the \n twice.
                    print = print.substring(nextEnd+1);
                } else {
                    print = print.substring(nextEnd);
                }
            }
        } else {
            android.util.Log.println(priority, LOG_TAG, print);
        }
    }

    private static String formatMessage(String message, Object... args) {
        String formatted;
        try {
            /*
             * {} is used by SLF4J so keep it compatible with that as it's easy to forget to use %s when you are
             * switching back and forth between server and client code.
             */
            formatted = String.format(message.replaceAll("\\{\\}", "%s"), args);
        } catch (Exception ex) {
            formatted = message + Arrays.toString(args);
        }
        return formatted;
    }
}

答案 5 :(得分:3)

下面的代码是Mark Buikema发布的内容的改进。它打破了新行的字符串。用于记录长JSON字符串。

  public static void dLong(String theMsg)
  {
    final int MAX_INDEX = 4000;
    final int MIN_INDEX = 3000;

    // String to be logged is longer than the max...
    if (theMsg.length() > MAX_INDEX)
    {
      String theSubstring = theMsg.substring(0, MAX_INDEX);
      int    theIndex = MAX_INDEX;

      // Try to find a substring break at a line end.
      theIndex = theSubstring.lastIndexOf('\n');
      if (theIndex >= MIN_INDEX)
      {
        theSubstring = theSubstring.substring(0, theIndex);
      }
      else
      {
        theIndex = MAX_INDEX;
      }

      // Log the substring.
      Log.d(APP_LOG_TAG, theSubstring);

      // Recursively log the remainder.
      dLong(theMsg.substring(theIndex));
    }

    // String to be logged is shorter than the max...
    else
    {
      Log.d(APP_LOG_TAG, theMsg);
    }
  }

答案 6 :(得分:2)

我们这个分页逻辑

    /*
     * StringBuffer sb - long text which want to show in multiple lines 
     * int lenth - lenth of line need
     */

public static void showInPage(StringBuffer sb, int lenth) {
    System.out.println("sb.length = " + sb.length());
    if (sb.length() > lenth) {

        int chunkCount = sb.length() / lenth; // integer division
        if ((chunkCount % lenth) > 1)
            chunkCount++;
        for (int i = 0; i < chunkCount; i++) {
            int max = lenth * (i + 1);
            if (max >= sb.length()) {
                System.out.println("");
                System.out.println("chunk " + i + " of " + chunkCount + ":"
                        + sb.substring(lenth * i));
            } else {
                System.out.println("");
                System.out.println("chunk " + i + " of " + chunkCount + ":"
                        + sb.substring(lenth * i, max));
            }
        }
    }

}

答案 7 :(得分:1)

提供我自己对Travis解决方案的看法,

void d(String msg) {
  println(Log.DEBUG, msg);
}

private void println(int priority, String msg) {
    int l = msg.length();
    int c = Log.println(priority, TAG, msg);
    if (c < l) {
        return c + println(priority, TAG, msg.substring(c+1));
    } else {
        return c;
    }
}

利用Log.println()返回写入的字节数以避免硬编码“4000”的事实。然后,递归地调用自己的消息部分,直到没有任何东西,无法记录。

答案 8 :(得分:1)

如果您的日志很长(例如,出于调试原因而记录数据库的整个转储等),则logcat可能会阻止过多的日志记录。要解决此问题,您可以添加超时evry x毫秒。

/**
 * Used for very long messages, splits it into equal chunks and logs each individual to
 * work around the logcat max message length. Will log with {@link Log#d(String, String)}.
 *
 * @param tag     used in for logcat
 * @param message long message to log
 */
public static void longLogDebug(final String tag, @NonNull String message) {
    int i = 0;

    final int maxLogLength = 1000;
    while (message.length() > maxLogLength) {
        Log.d(tag, message.substring(0, maxLogLength));
        message = message.substring(maxLogLength);
        i++;

        if (i % 100 == 0) {
            StrictMode.noteSlowCall("wait to flush logcat");
            SystemClock.sleep(32);
        }
    }
    Log.d(tag, message);
}

请注意,只能将其用于调试目的,因为它可能会停止阻塞主线程。

答案 9 :(得分:1)

int i = 3000;
while (sb.length() > i) {
    Log.e(TAG, "Substring: "+ sb.substring(0, i));
    sb = sb.substring(i);
}
Log.e(TAG, "Substring: "+ sb);

答案 10 :(得分:0)

我不知道增加logcat长度的任何选项,但我们可以找到不同的日志,如主日志,事件日志等。主日志通常包含其长度达到4Mb的所有内容..所以你可能得到你在日志终端丢失了什么。路径是:\ data \ logger。

答案 11 :(得分:0)

正如@mhsmith所述,LOGGER_ENTRY_MAX_PAYLOAD在最新的Android版本中为4068。但是,如果在其他答案中提供的代码段中使用4068作为最大消息长度,则消息将被截断。这是因为Android在邮件的开头和结尾添加了更多字符,这也很重要。其他答案使用4000限制作为解决方法。但是,可以用此代码真正使用整个限制(该代码从堆栈跟踪中生成一个标记,以显示称为日志的类名和行号,可以随时对其进行修改):

private static final int MAX_MESSAGE_LENGTH = 4068;

private enum LogType {
    debug,
    info,
    warning,
    error
}

private static void logMessage(LogType logType, @Nullable String message, @Nullable String tag) {
    logMessage(logType, message, tag, Thread.currentThread().getStackTrace()[4]);
}

private static void logMessage(LogType logType, @Nullable String message, @Nullable String customTag, StackTraceElement stackTraceElement) {
    // don't use expensive String.format
    String tag = "DASHBOARDS(" + stackTraceElement.getFileName() + "." + (!TextUtils.isEmpty(customTag) ? customTag : stackTraceElement.getMethodName()) + ":" + stackTraceElement.getLineNumber() + ")";
    int maxMessageLength = MAX_MESSAGE_LENGTH - (tag.length()) - 4; // minus four because android adds a letter showing the log type before the tag, e. g. "D/" for debug, and a colon and space are added behind it, i. e. ": "
    if (message == null || message.length() <= maxMessageLength) {
        logMessageInternal(logType, message, tag);
    } else {
        maxMessageLength -= 8; // we will add counter to the beginning of the message, e. g. "(12/15) "
        int totalChunks = (int) Math.ceil((float) message.length() / maxMessageLength);
        for (int i = 1; i <= totalChunks; i++) {
            int start = (i - 1) * maxMessageLength;
            logMessageInternal(logType, "(" + i + "/" + totalChunks + ") " + message.substring(start, Math.min(start + maxMessageLength, message.length())), tag);
        }
    }
}

private static void logMessageInternal(LogType logType, String message, String tag) {
    if (message == null) {
        message = "message is null";
    }
    switch (logType) {
        case debug:
            Log.d(tag, message);
            break;
        case info:
            Log.i(tag, message);
            break;
        case warning:
            Log.w(tag, message);
            break;
        case error:
            Log.e(tag, message);
    }
}

public static void d(String debug, String tag) {
    logMessage(LogType.debug, debug, tag);
}

答案 12 :(得分:0)

尽管提供的其他解决方案很有帮助,但我对它们不满意,因为它们没有涵盖日志的长度超过@ b0ti提到的LOGGER_ENTRY_MAX_LEN的两倍的情况。此外,由于无法动态获取LOGGER_ENTRY_MAX_LEN,因此即使是我下面的解决方案也不完美。如果有人知道这样做的方法,我很乐意在评论中听到!无论如何,这是我现在在我的代码中使用的解决方案:

final int loggerEntryMaxLength = 4000;
int logLength = loggerEntryMaxLength - 2 - TAG.length();
int i = 0;
while (output.length() / logLength > i) {
    int startIndex = i++ * logLength;
    int endIndex = i * logLength;
    Log.d(TAG, output.substring(startIndex, endIndex));
}
int startIndex = i * logLength;
Log.d(
        TAG,
        output.substring(
                startIndex,
                startIndex + (output.length() % logLength)
        )
);