Unix打印循环输出在一行上

Question

我创建了这个脚本，我想在一行打印输出，我该怎么做？ 这是我的剧本

#!/bin/bash

echo "enter start and stop numbers"

read start stop

while [ $start -lt $stop ]

do

echo $start

start=`expr $start + 1`

done

Answer 1

使用printf或echo -n。此外，尝试使用start=$(($start + 1))或start=$[$start + 1]而不是后退标记来增加变量。

#!/bin/bash

echo "enter start and stop numbers"
read start stop
while [ $start -lt $stop ]
do
    printf "%d " $start
    start=$(($start + 1))
done

---

#!/bin/bash

echo "enter start and stop numbers"
read start stop
while [ $start -lt $stop ]
do
    echo -n "$start "  # Space will ensure output has one space between them
    start=$[$start + 1]
done

Answer 2

使用

echo -n $start

退房： http://ss64.com/bash/echo.html

Answer 3

for（（i = 1; i <= 10; i ++）））;做echo -n $ i;完成回声-e“ \ n”