Android - 无法访问drawable nullpointer异常

时间:2012-01-21 14:05:02

标签: android map nullpointerexception overlay drawable

我试图在我的mapview上标记多个位置。有一个类从ItemizedOverlay扩展。有一个构造函数,它有两个参数(Drawable defaultMarker, Context c)

在我有mapview的MapActivity中,我试图定义一个drawable,这是创建逐项覆盖对象所必需的,但我总是有

java.lang.NullPointerException  caused by this line:




Drawable marker =this.getResources().getDrawable(R.drawable.pointer);

我用syso检查了这个变量,它对我来说似乎不是

I/System.out(430): android.graphics.drawable.BitmapDrawable@405ca538

我试图照顾解决方案。我发现的是在MapActivity的构造函数中初始化上下文

比我有以下错误:

Unable to instantiate activity ComponentInfo: java.lang.InstantiationException



MapController mc;
GeoPoint p;
MapView mapView;
Location loc;
    boolean move = true;
LocationManager mlocManager;
LocationListener mlocListener = new MyLocationListener();

    Context c
/* if constructor commented: nullpointer else instantiation exception */

MapActivity(Context cc){
    this.c=cc;
}


Drawable marker =c.getResources().getDrawable(R.drawable.pointer);

@Override
public void onCreate(Bundle savedInstanceState) {

    super.onCreate(savedInstanceState);
    System.out.println(this.getResources());
    mlocManager = (LocationManager) getSystemService(Context.LOCATION_SERVICE);
    setContentView(R.layout.map);
    tv = (TextView) findViewById(R.id.textView1);



    mapView = (MapView) findViewById(R.id.mapv);
    mapView.setBuiltInZoomControls(true);
    mc = mapView.getController();

    p = new GeoPoint((int) (lat1 * 1E6), (int) (lon1 * 1E6));

    Button bck = (Button) findViewById(R.id.backBtn);
    bck.setOnClickListener(new View.OnClickListener() {
        public void onClick(View vi) {
            mc.animateTo(p);

        }
    });

    class MapOverlay extends com.google.android.maps.Overlay {
        public boolean draw(Canvas canvas, MapView mapView, boolean shadow,
                long when) {
            super.draw(canvas, mapView, shadow);
            Point screenPts = new Point();
            mapView.getProjection().toPixels(p, screenPts);
            Bitmap bmp = BitmapFactory.decodeResource(getResources(),
                    R.drawable.pointer);
            canvas.drawBitmap(bmp, screenPts.x, screenPts.y - 50, null);
            return true;
        }
    }
}

1 个答案:

答案 0 :(得分:1)

而不是

this.getResources()

c.getResources()

用上下文。

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