数据库:选择最后的非空条目

时间:2012-01-23 19:26:19

标签: sql database postgresql select null

这是一个我一直绞尽脑汁的问题。假设我有一个表,其中包含一系列时间戳和一个部件号作为主键。该表存储增量更改,这意味着对于每个时间戳,如果字段更改,则记录该更改。如果该字段未更改,则对于新时间戳,它为NULL。 这是基本的想法。

 part | timestamp | x-pos | y-pos | status
------+-----------+-------+-------+--------
 a5   |       151 |     5 |    15 |      g
 a5   |       153 |  NULL |    17 |   NULL

(part, timestamp)是主键。第二条记录中的NULL表示自第一条记录以来未更改的值。

我希望能够选择按部件分组的每个字段的最新值。例如,给定上述条目,对于部分a5,结果将为153,5,17,g。

到目前为止,我已将此黑客一起查询。

    ((SELECT x-pos FROM part_changes WHERE x-pos IS NOT NULL
    ORDER BY timestamp DESC
    LIMIT 1)

    UNION

    (SELECT y-pos FROM part_changesWHERE y-pos IS NOT NULL
    ORDER BY timestamp DESC
    LIMIT 1)

    UNION

    (SELECT status FROM part_changes WHERE status IS NOT NULL
    ORDER BY timestamp DESC
    LIMIT 1))

但这会返回一个列,这意味着我可以使用group-by进行组织。

必须有更优雅的做事方式,例如以创造性的方式使用COALESCE或IS NULL。但是我被困住了,无法弄明白。有人有个主意吗?

不,我无法改变数据库结构。

编辑:鲁赫克有正确的想法。现在唯一的问题是按部分分组。我似乎无法通过多个部分绕过LIMIT 1进行分组。有任何想法吗?

mdahlman,我对postgresql中的分析函数不太熟悉。因此,如果该解决方案比复杂查询更容易,那么请务必发布您的想法。

编辑2:谢谢大家的帮助。我想我已经掌握了我需要做的事情。

4 个答案:

答案 0 :(得分:5)

而不是使用UNION,听起来你真的想要字段列表中的子查询。也就是说,您需要(SELECT ...) UNION (SELECT ...) UNION (SELECT ...)而不是SELECT (SELECT ...), (SELECT ...), (SELECT ...)


例如:

SELECT part,
       ( SELECT x_pos
           FROM part_changes
          WHERE part = pc.part
            AND x_pos IS NOT NULL
          ORDER
             BY timestamp DESC
          LIMIT 1
       ) AS x_pos,
       ( SELECT y_pos
           FROM part_changes
          WHERE part = pc.part
            AND y_pos IS NOT NULL
          ORDER
             BY timestamp DESC
          LIMIT 1
       ) AS y_pos,
       ( SELECT status
           FROM part_changes
          WHERE part = pc.part
            AND status IS NOT NULL
          ORDER
             BY timestamp DESC
          LIMIT 1
       ) AS status
  FROM ( SELECT DISTINCT
                part
           FROM part_changes
       ) AS pc
;

但是在这一点上我真的会考虑编写一个存储过程。


可替换地:

SELECT DISTINCT
       part,
       FIRST_VALUE(x_pos) OVER
         ( PARTITION BY part
               ORDER BY CASE WHEN x_pos IS NULL
                             THEN NULL
                             ELSE TIMESTAMP
                         END DESC NULLS LAST
         ) AS x_pos,
       FIRST_VALUE(y_pos) OVER
         ( PARTITION BY part
               ORDER BY CASE WHEN y_pos IS NULL
                             THEN NULL
                             ELSE TIMESTAMP
                         END DESC NULLS LAST
         ) AS y_pos,
       FIRST_VALUE(status) OVER
         ( PARTITION BY part
               ORDER BY CASE WHEN status IS NULL
                             THEN NULL
                             ELSE TIMESTAMP
                         END DESC NULLS LAST
         ) AS status
  FROM part_changes
;

答案 1 :(得分:2)

只有一个部分,这应该给你答案..感谢 ruakh

但我不喜欢这个版本..

SELECT 
    (SELECT timestamp  FROM part_changes WHERE part = $part 
    ORDER BY timestamp DESC
    LIMIT 1) as timestamp,

    (SELECT x-pos FROM part_changes WHERE part = $part and x-pos IS NOT NULL
    ORDER BY timestamp DESC
    LIMIT 1) as xpos,

    (SELECT y-pos FROM part_changes WHERE part = $part and  y-pos IS NOT NULL
    ORDER BY timestamp DESC
    LIMIT 1) as ypos,

    (SELECT status FROM part_changes WHERE part = $part and status IS NOT NULL
    ORDER BY timestamp DESC
    LIMIT 1)) as status

答案 2 :(得分:1)

相关时间戳列表:

select max timestamp from part_changes where x_POS is not null group by part

您可以将其设为视图:让我们调用此view1

SELECT part_changes.part, part_changes.x-pos 
FROM part_changes left join view1 on part_changes.part = view1.part
WHERE x-pos IS NOT NULL 
 AND part_changes.timestamp = view1.timestamp 
GROUP BY part_changes.part

看看我要去哪里?这应该为您提供x-pos的完整列表。

答案 3 :(得分:0)

鲁哈克是对的。替代方法:使用SQL-CLR编写用户定义的聚合。此聚合可以在您的行上方自上而下运行,并记住每列的第一个非空值。

您也可以在应用程序中执行此操作。使您的程序按批次顺序请求行,例如10行。如上所述聚合这些批次。如果在当前批次完成后,空列就会获得下一批。

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