PowerShell - 枚举集合并更改集合

时间:2012-01-25 15:31:36

标签: sharepoint powershell foreach

如何修复此脚本?

是的,我在foreach循环中更改了集合,这就是导致此错误的原因。

枚举集合时发生错误:集合已修改;枚举操作可能无法执行.. 在C:\ Users \ user \ Documents \ PowerShell \ ChangeAllListsV2.ps1:47 char:20 + foreach<<<< ($ webLists中的$ list)     + CategoryInfo:InvalidOperation :( Microsoft.Share ... on + SPEnumerator:SPEnumerator)[],RuntimeException     + FullyQualifiedErrorId:BadEnumeration

#Script change in all lists the required field property "testfield" to false


#Part 0 - Configuration

$urlWebApp = "http://dev.sharepoint.com"
$countFound = 0
$countList = 0
$countFoundAndChange = 0

#Part 1 - PreScript  

$snapin = Get-PSSnapin | Where-Object {$_.Name -eq "Microsoft.SharePoint.Powershell"}

if ($snapin -eq $null)

{
    Write-Host “Loading SharePoint Powershell”
    Add-PSSnapin Microsoft.SharePoint.Powershell
}

#Part 2 - Script

$webApp = Get-SPWebApplication $urlWebApp

#$webApp | fl

    $webAppSites = $webApp.sites

    foreach($site in $webAppSites)
    {
        Write-Host "***********************************************************************"
        Write-Host "Found site: " $site -foreground blue

        $siteAllWebs = $site.AllWebs

        foreach($web in $siteAllWebs)
        {
            Write-Host "Found web: " $web -foreground blue
            #$web | fl

           $webLists = $web.Lists

            foreach($list in $webLists)
            {
             $countList ++

             Write-Host "Found list: " $list -foreground blue

                #Change list property

                $field = $Null
                $field = $list.Fields["testfield"]

                    if($field){
                    Write-Host "Field found: " $list -foreground green
                    #Write-Host "in web: " $web -foreground green
                    $countFound ++

                        try{

                            if($field.Required)
                            {

                            #######################################################
                            $field.Required = $False
                            $field.Update()
                            #######################################################

                            $field = $Null
                            Write-Host "Done!: Change list: " $list -foreground  green
                            $countFoundAndChange ++                    

                            }else{ 
                            Write-Host "Already!: Change list: " $list -foreground  green       

                            }

                        }
                        catch{
                            $field = $Null
                            Write-Host "Error!: Change list: " $list -foreground red
                            Write-Host "in web: " $web -foreground red
                            $_

                        }

                    }


            } 


        }


    }



Write-Host "Found lists: " $countList
Write-Host "Found lists with column [testfield]: " $countFound
Write-Host "Change lists with column [testfield]: " $countFoundAndChange

4 个答案:

答案 0 :(得分:20)

SPListCollection倾向于在更新其属性(字段,事件接收器等)时修改集合。您可以改为使用for循环:

for ($i = 0; $i -lt $webLists.Count; $i++)
{
  $list = $web.Lists[$i];
  # ...
}

答案 1 :(得分:3)

您可以尝试将当前正在迭代的集合复制到另一个集合(数组或列表),然后迭代该新集合。

这样的事情:

$collection = @(1, 2, 3, 4)
$copy = @($collection)
$collection[0] = 10
$collection -join " "
$copy -join " "

上面的代码给出了以下输出:

10 2 3 4
1 2 3 4

请注意,$copy变量指的是不同的集合。

答案 2 :(得分:0)

检查:http://soreddymanjunath.blogspot.in/2014/07/collection-was-modified-enumeration.html

以下是同一问题的另一个例子

    if($web.IsMultilingual -eq $true  )
  {

    foreach($cul in $web.SupportedUICultures)
   {
     if($cul.LCID -ne  $webCul.LCID -and $cul.LCID -ne "1033")
     {    

       $web.RemoveSupportedUICulture($cul)


      }
    }
 $web.Update()
  }

第一次它将通过循环foreach将删除支持的文化为第一次迭代,然后它会抛出异常“收集被修改;枚举操作可能不会执行“,

解决上述问题是将存储到要在Arraylist中修改的值并尝试修改哪个将解决问题,在这里我存储名为enumcul的Arraylist并将值插入其中并修改它...

$enumcul=New-Object Collections.ArrayList
$i=0
if($web.IsMultilingual -eq $true  )
  {

    foreach($cul in $web.SupportedUICultures)
   {
     if($cul.LCID -ne  $webCul.LCID -and $cul.LCID -ne "1033")
     {

      $enumcul.Insert($i, $cul)
      $i=$i+1
      }

   }


 foreach( $k in $enumcul)
 {

    $web.RemoveSupportedUICulture($k)
    $web.Update()
 }

答案 3 :(得分:0)

我知道这是一个很老的话题。这是给最终进入此页面寻找答案的任何人的。

这个想法是,像其他答案所建议的那样,将集合(使用 clone()方法)复制到另一个并迭代“另一个”并在循环内修改原始变量,而不必使用 for 代替 foreach

ArrayList类型的集合:

[System.Collections.ArrayList]$collection1 = "Foo","bar","baz"
$($collection1.Clone()) | foreach {
$collection1.Remove("bar")
}

输出:

PS H:\> $collection1
Foo
baz

Hashtable类型的集合:

[System.Collections.Hashtable]$collection2 = @{
        "Forum" = "Stackoverflow"
        "Topic" = "PowerShell"
        }

$($collection2.Clone())| foreach {
$collection2.Remove("Forum")
}

输出: PS H:> $ collection2

Name                           Value                                                              
----                           -----                                                              
Topic                          PowerShell                                                         

还有一个基本数组:

[System.Array]$collection3 = 1, 2, 3, 4
$($collection3.Clone()) | foreach {
$collection3[$collection3.IndexOf($_)] = 10
}

输出:

PS H:\> $collection3
10
10
10
10

只要您的收藏不是固定大小的。

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