如何将位图旋转90度

Question

android canvas.drawBitmap(visiblePage, 0, 0, paint);

中有一条声明

当我添加canvas.rotate(90)时，没有效果。但如果我写

canvas.rotate(90)
canvas.drawBitmap(visiblePage, 0, 0, paint);

我没有绘制位图。那我该怎么做呢？

Answer 1

您也可以试试这个

Matrix matrix = new Matrix();

matrix.postRotate(90);

Bitmap scaledBitmap = Bitmap.createScaledBitmap(bitmapOrg, width, height, true);

Bitmap rotatedBitmap = Bitmap.createBitmap(scaledBitmap, 0, 0, scaledBitmap.getWidth(), scaledBitmap.getHeight(), matrix, true);

然后，您可以使用旋转的图像通过

在imageview中进行设置

imageView.setImageBitmap(rotatedBitmap);

Answer 2

public static Bitmap RotateBitmap(Bitmap source, float angle)
{
      Matrix matrix = new Matrix();
      matrix.postRotate(angle);
      return Bitmap.createBitmap(source, 0, 0, source.getWidth(), source.getHeight(), matrix, true);
}

从资源中获取位图：

Bitmap source = BitmapFactory.decodeResource(this.getResources(), R.drawable.your_img);

Answer 3

Kotlin

的短扩展

fun Bitmap.rotate(degrees: Float): Bitmap {
    val matrix = Matrix().apply { postRotate(degrees) }
    return Bitmap.createBitmap(this, 0, 0, width, height, matrix, true)
}

用法：

val rotatedBitmap = bitmap.rotate(90)

Answer 4

下面是在android

中旋转或调整图像大小的代码

public class bitmaptest extends Activity {
    @Override
    public void onCreate(Bundle icicle) {
        super.onCreate(icicle);
        LinearLayout linLayout = new LinearLayout(this);

        // load the origial BitMap (500 x 500 px)
        Bitmap bitmapOrg = BitmapFactory.decodeResource(getResources(),
               R.drawable.android);

        int width = bitmapOrg.width();
        int height = bitmapOrg.height();
        int newWidth = 200;
        int newHeight = 200;

        // calculate the scale - in this case = 0.4f
        float scaleWidth = ((float) newWidth) / width;
        float scaleHeight = ((float) newHeight) / height;

        // createa matrix for the manipulation
        Matrix matrix = new Matrix();
        // resize the bit map
        matrix.postScale(scaleWidth, scaleHeight);
        // rotate the Bitmap
        matrix.postRotate(45);

        // recreate the new Bitmap
        Bitmap resizedBitmap = Bitmap.createBitmap(bitmapOrg, 0, 0,
                          width, height, matrix, true);

        // make a Drawable from Bitmap to allow to set the BitMap
        // to the ImageView, ImageButton or what ever
        BitmapDrawable bmd = new BitmapDrawable(resizedBitmap);

        ImageView imageView = new ImageView(this);

        // set the Drawable on the ImageView
        imageView.setImageDrawable(bmd);

        // center the Image
        imageView.setScaleType(ScaleType.CENTER);

        // add ImageView to the Layout
        linLayout.addView(imageView,
                new LinearLayout.LayoutParams(
                      LayoutParams.FILL_PARENT, LayoutParams.FILL_PARENT
                )
        );

        // set LinearLayout as ContentView
        setContentView(linLayout);
    }
}

您还可以查看此链接了解详情：http://www.anddev.org/resize_and_rotate_image_-_example-t621.html

Answer 5

默认情况下，旋转点是画布的（0,0）点，我的猜测是您可能想要围绕中心旋转它。 我做到了：

protected void renderImage(Canvas canvas)
{
    Rect dest,drawRect ;

    drawRect = new Rect(0,0, mImage.getWidth(), mImage.getHeight());
    dest = new Rect((int) (canvas.getWidth() / 2 - mImage.getWidth() * mImageResize / 2), // left
                    (int) (canvas.getHeight()/ 2 - mImage.getHeight()* mImageResize / 2), // top
                    (int) (canvas.getWidth() / 2 + mImage.getWidth() * mImageResize / 2), //right
                    (int) (canvas.getWidth() / 2 + mImage.getHeight()* mImageResize / 2));// bottom

    if(!mRotate) {
        canvas.drawBitmap(mImage, drawRect, dest, null);
    } else {
        canvas.save(Canvas.MATRIX_SAVE_FLAG); //Saving the canvas and later restoring it so only this image will be rotated.
        canvas.rotate(90,canvas.getWidth() / 2, canvas.getHeight()/ 2);
        canvas.drawBitmap(mImage, drawRect, dest, null);
        canvas.restore();
    }
}

Answer 6

使用Java createBitmap()方法可以传递学位。

Bitmap bInput /*your input bitmap*/, bOutput;
float degrees = 45; //rotation degree
Matrix matrix = new Matrix();
matrix.setRotate(degrees);
bOutput = Bitmap.createBitmap(bInput, 0, 0, bInput.getWidth(), bInput.getHeight(), matrix, true);

Answer 7

如果你旋转位图，90 180 270 360就可以了，但是对于其他度数，画布会绘制不同大小的位图。

所以，最好的方法是

canvas.rotate(degree,rotateCenterPoint.x,rotateCenterPoint.y);  
canvas.drawBitmap(...);
canvas.rotate(-degree,rotateCenterPoint.x,rotateCenterPoint.y);//rotate back

Answer 8

我将进一步简化comm1x的 Kotlin扩展功能：

fun Bitmap.rotate(degrees: Float) =
    Bitmap.createBitmap(this, 0, 0, width, height, Matrix().apply { postRotate(degrees) }, true)

Answer 9

如果您的目标是在imageView或文件中使用旋转图像，则可以使用Exif来实现该目标。支持库现在提供：https://android-developers.googleblog.com/2016/12/introducing-the-exifinterface-support-library.html

以下是它的用法，但要实现您的目标，您必须检查库api文档。我只是想提一下旋转位图并不总是最好的方法。

Uri uri; // the URI you've received from the other app
InputStream in;
try {
  in = getContentResolver().openInputStream(uri);
  ExifInterface exifInterface = new ExifInterface(in);
  // Now you can extract any Exif tag you want
  // Assuming the image is a JPEG or supported raw format
} catch (IOException e) {
  // Handle any errors
} finally {
  if (in != null) {
    try {
      in.close();
    } catch (IOException ignored) {}
  }
}

int rotation = 0;
int orientation = exifInterface.getAttributeInt(
    ExifInterface.TAG_ORIENTATION,
    ExifInterface.ORIENTATION_NORMAL);
switch (orientation) {
  case ExifInterface.ORIENTATION_ROTATE_90:
    rotation = 90;
    break;
  case ExifInterface.ORIENTATION_ROTATE_180:
    rotation = 180;
    break;
  case ExifInterface.ORIENTATION_ROTATE_270:
    rotation = 270;
    break;
}

依赖

  

编译“com.android.support:exifinterface:25.1.0”

Answer 10

请小心来自comm1x和Gnzlt的java平台调用中的Bitmap类型，因为它可能返回null。我认为，如果参数可以是任何Number并使用infix以提高可读性，这也将更加灵活，具体取决于您的编码风格。

infix fun Bitmap.rotate(degrees: Number): Bitmap? {
    return Bitmap.createBitmap(
        this,
        0,
        0,
        width,
        height,
        Matrix().apply { postRotate(degrees.toFloat()) },
        true
    )
}

如何使用？

bitmap rotate 90
// or
bitmap.rotate(90)