我已经对这个问题进行了一些研究,但是每个php形式都彼此不同,所以其他人的解决方案可能对我不起作用。 我希望有一个链接,说“重新加载验证码”,当它点击它重新加载而不刷新页面。 我的表单确实使用了AJAX和javascript,我猜这是为了做到这一点所需要的。
我的表单的javascript就像:
jQuery(document).ready(function() {
$('.contactform').submit(function() {
var action = $(this).attr('action');
var form = this;
$('.submit', this).attr('disabled', 'disabled').after(
'<img src="assets/ajax-loader.gif" class="loader" />');
$('.message', this).slideUp(750, function() {
$(this).hide();
$.post(action, {
name: $('.name', form).val(),
email: $('.email', form).val(),
phone: $('.phone', form).val(),
comments: $('.comments', form).val(),
verify: $('.verify', form).val()
},
function(data) {
$('.message', form).html(data);
$('.message', form).slideDown('slow');
$('img.loader', form).fadeOut('fast', function() {
$(this).remove();
});
$('.submit', form).removeAttr('disabled');
if (data.match('success') != null)
$('.message', form).show().delay(5000).fadeOut();
});
});
return false;
});
});
PHP表格如下:
<?php if (!isset($_SESSION)) session_start();
if(!$_POST) exit;
if (!defined("PHP_EOL")) define("PHP_EOL", "\r\n");
$address = "email@domain.com";
$bcc = "email@domain.com";
$twitter_active = 0;
$twitter_user = ""; // Your user name
$consumer_key = "";
$consumer_secret = "";
$token = "";
$secret = "";
$name = $_POST['name'];
$email = $_POST['email'];
$phone = $_POST['phone'];
$dayin = $_POST['dayin'];
$dayout = $_POST['dayout'];
$comments = $_POST['comments'];
if (isset($_POST['verify'])) :
$posted_verify = $_POST['verify'];
$posted_verify = md5($posted_verify);
else :
$posted_verify = '';
endif;
// Important Variables
$session_verify = $_SESSION['verify'];
if (empty($session_verify)) $session_verify = $_COOKIE['verify'];
$error = '';
if(trim($name) == '') {
$error .= '<li>Your name is required.</li>';
}
if(trim($email) == '') {
$error .= '<li>Your e-mail address is required.</li>';
} elseif(!isEmail($email)) {
$error .= '<li>You have entered an invalid e-mail address.</li>';
}
if(trim($phone) == '') {
$error .= '<li>Your phone number is required.</li>';
} elseif(!is_numeric($phone)) {
$error .= '<li>Your phone number can only contain digits (numbers
and no spaces).</li>';
}
if(trim($comments) == '') {
$error .= '<li>You must enter a message to send.</li>';
}
if($session_verify != $posted_verify) {
$error .= '<li>The verification code you entered is incorrect.
</li>';
}
if($error != '') {
echo '<div class="error_message">Attention! Please correct the
errors below and try again.';
echo '<ul class="error_messages">' . $error . '</ul>';
echo '</div>';
} else {
if(get_magic_quotes_gpc()) { $comments = stripslashes($comments); }
$e_subject = 'Website Enquiry';
$msg = '<html><body> </body></html>';
if($twitter_active == 1) {
$twitter_msg = $name . " - " . $comments . ". You can contact " .
$name . " via email, " . $email ." or via phone " . $phone . ".";
twittermessage($twitter_user, $twitter_msg, $consumer_key,
$consumer_secret, $token, $secret);
}
$msg = wordwrap( $msg, 70 );
$headers = "From: $email\r\nBCC:{$bcc}\r\n" . PHP_EOL;
$headers .= "Reply-To: $email" . PHP_EOL;
$headers .= "MIME-Version: 1.0" . PHP_EOL;
$headers .= "Content-type: text/html; charset=utf-8" . PHP_EOL;
$headers .= 'Content-Transfer-Encoding: 8bit'. "\n\r\n" . PHP_EOL;
if(mail($address, $e_subject, $msg, $headers)) {
echo "<fieldset>";
echo "<div id='success_page'>";
echo "<img src='success.png' align='absmiddle' style='padding-right:5px;'
/><strong>Email Sent Successfully.</strong>";
echo "</div>";
echo "</fieldset>";
} else {
echo 'ERROR!'; // Dont Edit.
}
}
function twittermessage($user, $message, $consumer_key, $consumer_secret, $token,
$secret) { // Twitter Direct Message function, do not edit.
require_once('twitter/EpiCurl.php');
require_once('twitter/EpiOAuth.php');
require_once('twitter/EpiTwitter.php');
$Twitter = new EpiTwitter($consumer_key, $consumer_secret);
$Twitter->setToken($token, $secret);
$direct_message = $Twitter->post_direct_messagesNew( array('user' => $user, 'text'
=> $message) );
$tweet_info = $direct_message->responseText;
}
?>
(我把$ msg中的电子邮件发送出去,因为代码太多了,我认为没有必要包含它)
我的表单上的验证码的HTML如下:
<label for="verify" accesskey="V"> <img src="image.php"
alt="Image verification" border="0"/></label>
<input name="verify" type="text" id="verify" class="verify" size="6" value=""
style="width: 50px;" />
任何人都知道我应该逐步做什么? (注意:我仍然是php和ajax的业余爱好者)...哦,不,如果你想的话,我不想使用reCaptcha:)
答案 0 :(得分:0)
这应该给你一个headstart,这个asssums image.php生成图像并更新session / cookie变量。我们更新图像以包含缓存清除字符串,以便它应该更新图像和会话变量。
<强> HTML 强>
<button id="reloadCaptcha">Reload Captcha</button>
更改HTML
<img id="captchaImage" src="image.php" alt="Image verification" border="0"/>
<强> JS 强>
$('button#reloadCaptcha').click(function() {
$('img#captchaImage').attr('src', 'image.php?'+new Date().getTime());
});
显然未经测试,但应该给你一个良好的实施开始。