Question

请准备以下表格：

 Clients (ID, LastName)

 Orders (ID, ClientID)

 Payments (ID, OrderID, PaymentDate, Amount)

我需要一个SQL查询，它会返回在给定日期之后付款的客户LastNames列表，该日期总计至少有一些金额。

示例：检索2011年1月1日之后至少总计1,000美元的所有客户。

我可以获得自指定日期（2011年1月1日）以来付款的客户：

 SELECT Clients.LastName
 FROM   Clients
 WHERE  Clients.ID IN (SELECT Orders.ClientID
                       FROM   Orders
                       WHERE  Orders.ID IN (SELECT Payments.OrderID
                                            FROM   Payments
                                            WHERE  Payments.PaymentDate >= '2011-01-01'))

我无法弄清楚如何只获得这些付款累计至少一定金额的客户。

Answer 1

我认为你可以使用这样的东西：

select c.ID, c.LastName
from Clients c
join Orders o on o.ClientId=c.Id
join Payments p on p.OrderId=o.Id
where p.PaymentDate >= '2011-01-01'
group by c.ID, c.LastName
having sum(p.PaymentAmount) > 1000

Answer 2

SELECT Clients.ID, Clients.LastName--, SUM(Amount) AS TotalPayments
FROM Clients
JOIN Orders ON Clients.ID = Orders.ClientId
JOIN Payments ON Payments.OrderId = Orders.Id
WHERE Payments.PaymentDate > '20110101'
GROUP BY Clients.ID, Clients.LastName
HAVING SUM(Amount) >= 1000

如果您想知道确切的总和 - 取消注释第一行查询中的注释部分

Answer 3

我相信这样的事情应该有效：

Clients.LastName
FROM   Clients
WHERE  Clients.ID IN (SELECT Orders.ClientID
                   FROM   Orders
                   WHERE  Orders.ID IN (SELECT Payments.OrderID
                                        FROM   Payments
                                        WHERE  Payments.PaymentDate >= '2011-01-01' 
                                        GROUP BY Payments.OrderId 
                                        HAVING SUM(Payments.Amount) > 1000))

带有相关表和的SQL查询

3 个答案: