基本连接和聚合?

时间:2012-01-31 20:58:39

标签: sql count aggregate inner-join

我有表A,表B和表C.

我想从表A中选择2个字段,从表B中选择一个字段(我假设这两个字段之间是内连接),并在表C中找到表B上标识符的每个记录的计数。

所以我会:

OpeartiveId | OperativeNumber | JobLocation | CountOfJobIdInWorkTable

编辑:

Operative
OperativeId
OperativeNumber

Jobs
JobId
JobLocation

Work
JobId
OperativeId

4 个答案:

答案 0 :(得分:2)

假设您还希望a和b中的记录在c中没有匹配记录,则需要外部联接:

select a.pk_a, b.pk_b, count(c.pk_c) 
from a 
inner join b on a.pk_a = b.pk_a 
left outer join c on b.pk_b = c.pk_b 
group by a.pk_a, b.pk_b;

答案 1 :(得分:1)

将其翻译成您的实际架构并尝试:

select a.one, a.two, b.three, count(c.id)
from a
join b on a.id=b.id
left join c on c.bid=b.id
group by a.one, a.two, b.three, b.id

答案 2 :(得分:1)

不确定这是否是您要找的。看着你提供的文件,我想出了这个。

select o.operativeId, o.OperativeNumber, j.JobLocation, COUNT(w.jobId)
from dbo.Operative o
Inner join works w
    ON o.OperativeID = w.OperativeId
INNER JOIN jobs j
ON w.jobId = j.jobId
GROUP by o.operativeId, o.OperativeNumber, j.JobLocation

答案 3 :(得分:-1)

select a.a,a.b,b.a,(select count(*) from c where c.b_id = b.id)
from a 
join b on a.b_id = b.id
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