Question

如何检查pygtk窗口是否在当前桌面上？

我正在修理的一个程序：

if self.pymp.window.get_property('visible'):
    self.pymp.window.hide()
else:
    self.pymp.window.move(self.pymp.position[0], self.pymp.position[1])
    self.pymp.window.show()
    self.pymp.window.present()

我想替换：

if self.pymp.window.get_property('visible'):

使用：

if self.pymp.window.get_property('visible') and window_is_on_current_workspace(self.pymp.window):

我可以window_is_on_current_workspace(window)实施wnck作为：

def window_is_on_current_workspace(window):
    import wnck
    v = wnck.screen_get_default() # needed due to known bug
    xid = window.window.xid
    win = None
    while win is None:
        win = wnck.window_get(xid)
        if gtk.events_pending():
            gtk.main_iteration()
    wor = win.get_screen().get_active_workspace()
    return win.is_on_workspace(wor)

它有效，但它很蹩脚。有更好的方法吗？

Answer 1

你可以使用wnck。这是一个样本，

from gi.repository import Wnck # import wnck for gtk2

screen = Wnck.Screen.get_default()

def window_is_on_current_workspace(window):
    for win in screen.get_windows():
        if win.get_pid() == os.getpid(): # You could use other methods to determine if you've the right window, like window.name; Just make sure you can uniquely identify it
            return win.get_workspace() == s.get_active_workspace()

        # This works if you have only one window per process, it's just an example. You can use any method to match your gtk window with the x11 window returned by wnck.Screen

检查当前桌面上是否有窗口？

1 个答案: