Question

我想要的是将NSDictionary对象转换为NSInteger.im解析json对象并将其存储在NSMutableArray中，然后将其存储在名为boy的NSDictionary对象中。你们可以帮助我。下面是代码

        NSURLRequest *request = [NSURLRequest requestWithURL:jsonurl cachePolicy:NSURLRequestUseProtocolCachePolicy timeoutInterval:60.0];
connection1=[[[NSURLConnection alloc] initWithRequest:request delegate:self] autorelease];


NSLog(@"jsonurl:%@",jsonurl);
self.jsonData=[NSData dataWithContentsOfURL:jsonurl];

NSDictionary *items=[NSJSONSerialization JSONObjectWithData:self.jsonData options:NSJSONReadingMutableLeaves error:nil];
NSLog(@"blah:%@",jsonArray);
items1 = [items objectForKey:@"ThingsTodo"];

story = [[NSMutableArray array]retain];
media1 = [[NSMutableArray array]retain];

url=[[NSMutableArray array]retain];
media2=[[NSMutableArray array]retain];
descriptiondesc=[[NSMutableArray array]retain];
for (NSDictionary *item in items1)
{
    [self.story addObject:[item objectForKey:@"Name"]];
    [self.media1 addObject:[item objectForKey:@"Status"]];
    [self.media2 addObject:[item objectForKey:@"Image"]];

}
    NSDictionary *boy=[self.media1 objectAtIndex:indexPath.row];

Answer 1

将nsdictionary值放入nsstring，然后选择NSInteger并执行以下操作：

NSInteger n = [strVal intValue];

Answer 2

更具体的说法＆＃34; intValue＆＃34;给出＆＃34; int＆＃34;而＆＃34; integerValue＆＃34;返回＆＃34; NSInteger＆＃34;所以

NSInteger n = [strVal integerValue];

如何将NSDictionary值转换为NSInteger

2 个答案: