Question

我需要使用带有4个字符串参数的POST方法创建REST服务

我将其定义如下：

[WebInvoke(UriTemplate = "/", Method = "POST", BodyStyle= WebMessageBodyStyle.WrappedRequest)]
public Stream ProcessPost(string p1, string p2, string p3, string p4)
{
    return Execute(p1, p2, p3, p4);
}

我想用代码调用它，如下所示：

        string result = null;
        HttpWebRequest req = WebRequest.Create(url) as HttpWebRequest;
        req.Method = "POST";
        req.ContentType = "application/x-www-form-urlencoded";

        string paramz = string.Format("p1={0}&p2={1}&p3={2}&p4={3}", 
            HttpUtility.UrlEncode("str1"),
            HttpUtility.UrlEncode("str2"),
            HttpUtility.UrlEncode("str3"),
            HttpUtility.UrlEncode("str4")
            );

        // Encode the parameters as form data:
        byte[] formData =
            UTF8Encoding.UTF8.GetBytes(paramz);
        req.ContentLength = postData.Length;

        // Send the request:
        using (Stream post = req.GetRequestStream())
        {
            post.Write(formData, 0, formData.Length);
        }

        // Pick up the response:
        using (HttpWebResponse resp = req.GetResponse()
                                      as HttpWebResponse)
        {
            StreamReader reader =
                new StreamReader(resp.GetResponseStream());
            result = reader.ReadToEnd();
        }

        return result;

但是，客户端代码返回代码400：错误请求

我做错了什么？

谢谢

Answer 1

我会说不支持form-urleconded格式。 WebInvoke属性的RequestFormat属性是WebMessageFormat枚举类型，它只将JSON和XML定义为有效格式。

http://msdn.microsoft.com/en-us/library/system.servicemodel.web.webmessageformat.aspx

Answer 2

我会说UriTemplate中的参数如下所示

[OperationContract]
[WebInvoke(UriTemplate = "{p1}/{p2}/{p3}/{p4}", Method = "POST", BodyStyle = WebMessageBodyStyle.WrappedRequest)]
string ProcessPost(string p1, string p2, string p3, string p4);

并使用以下代码调用

string result = null; 
string uri = "http://localhost:8000/ServiceName.svc/1/2/3/4";

HttpWebRequest req = WebRequest.Create(uri) as HttpWebRequest;
req.KeepAlive = false;
req.Method = "POST";

using (HttpWebResponse resp = req.GetResponse() as HttpWebResponse) 
   { 
       StreamReader reader = new StreamReader(resp.GetResponseStream()); 
       result = reader.ReadToEnd(); 
   }

对我来说很好。希望这种方法很有用。

WCF REST服务POST方法

2 个答案: