Question

我需要能够在此选择查询中对来自Aus_Postcodes的邮政编码进行分组，因为正在发生的是要约正在循环。

当前查询：

SELECT approved_business.*, 
       business_stores.*, 
       group_concat(offer ORDER BY offer ASC SEPARATOR ',') as offers, 
       Aus_Postcodes.state as AusState 
FROM  approved_business, 
      business_stores, 
      Real_Cash_Offers, 
      Aus_Postcodes 
WHERE approved_business.id = business_stores.business_id AND 
      Real_Cash_Offers.business_id = approved_business.id AND 
      Real_Cash_Offers.storeid = business_stores.storeid AND 
      business_stores.postcode = Aus_Postcodes.postcode AND 
      approved_business.id = '1288' 
GROUP BY approved_business.id 
LIMIT 1

以下是示例输出，我已将其编码为JSON，因为这是我们系统使用的。

[{"id":"1288","tradingname":"Loretta Adams Bridal & Evening Wear","listed":"2012-01-26 19:26:24","pictureurl":"","business_id":"1288","storeid":"1","phone":"6139379210","street":"266 Keilor Rd","suburb":"Essendon North","state":"1","postcode":"3041","discription":"","offers":"1000|70,1000|70,1000|70,300|15,300|15,300|15,500|30,500|30,500|30","AusState":"VIC,VIC,VIC,VIC,VIC,VIC,VIC,VIC,VIC"}]

Answer 1

将group_concat(offer ORDER BY offer ASC SEPARATOR ',') as offers更改为group_concat(DISTINCT offer ORDER BY offer ASC SEPARATOR ',') as offers。

不止一个地方有相同的邮政编码导致问题

1 个答案: