订阅中的SSRS默认参数值

时间：2012-02-07 16:50:17

标签： reporting-services ssrs-2008

我有一个报告，其中包含两个用户输入的日期参数。我想创建一个在周五运行的订阅，该订阅将在前一周的周日到周六期间进行。因此，例如，对于即将到来的星期五，订阅将在1月29日 - 2月4日进行。我已尝试=Now(), =Today(), @ExecutionTime然后减去天数，但我得到的只是错误。这可能吗？

我确实看到了这个链接，但我想知道是否有更好的方法。 http://www.sqlservercentral.com/articles/Development/datadrivensubscriptions/2432/

SSRS 2008

4 个答案:

答案 0 :(得分：6)

是的，我已经这样做了，请看这篇文章https://stackoverflow.com/a/5539615/168703 您可以创建一个获取日期范围的数据集，并在报告中使用它。然后您的订阅可以使用此日期范围并动态更改，而无需每天/每周/每月/每年/等手动更改。

此处也转载，这是您最灵活的解决方案：

我还会分享一组我使用的常用日期函数。只需将其创建为表值函数：

set ANSI_NULLS ON
set QUOTED_IDENTIFIER ON
go

CREATE FUNCTION [dbo].[udfCommonDates] (@date datetime)
RETURNS @t table (week_start datetime,
                  week_end datetime,
                  lastweek_start datetime,
                  lastweek_end datetime,
                  month_start datetime,
                  month_end datetime,
                  lastmonth_start datetime,
                  lastmonth_end datetime,
                  yesterday_start datetime,
                  yesterday_end datetime,
                  today_start datetime,
                  today_end datetime,
                  thisweek_monday_start datetime,
                  thisweek_monday_end datetime,
                  year_start datetime,
                  year_end datetime,
                  tomorrow_noon datetime,
                  today_noon datetime,
                  date_only datetime)
BEGIN
   INSERT @t
   SELECT
   dbo.get_week_start ( @date ) AS week_start,
   dbo.get_week_end   ( @date ) AS week_end,
   dbo.get_week_start ( DATEADD(d, -7, @date ) ) AS lastweek_start,
   dbo.get_week_end   ( DATEADD(d, -7, @date ) ) AS lastweek_end,
   dbo.get_month_start( @date ) AS month_start,
   dbo.get_month_end  ( @date ) AS month_end,
   dbo.get_month_start ( DATEADD(m,-1, @date) ) AS lastmonth_start,
   dbo.get_month_end  ( DATEADD(m,-1,@date) ) AS lastmonth_end,
   dbo.get_yesterday_start ( @date ) AS yesterday_start,
   dbo.get_yesterday_end ( @date ) AS yesterday_end,
   dbo.get_today_start (@date) AS today_start,
   dbo.get_today_end ( @date ) AS today_end,
   dbo.get_weekday_start(1,@date) AS thisweek_monday_start,
   dbo.get_weekday_end(1,@date) AS thisweek_monday_end,
   dbo.get_year_start(@date) AS year_start,
   dbo.get_year_end(@date) AS year_end,  
   dbo.get_tomorrow_noon(@date) AS TomorrowNoon,
   dbo.get_today_noon(@date) AS TodayNoon,
   dbo.get_date_only(@date) AS DateOnly
RETURN
END

以下是这些的标量值函数：

    CREATE FUNCTION [dbo].[get_date_only] (@date datetime)
    RETURNS datetime
    WITH SCHEMABINDING, RETURNS NULL ON NULL INPUT
    AS    
    BEGIN
        RETURN dateadd(day, DateDiff(day, 0, GetDate()), 0)
    END
    GO

CREATE FUNCTION [dbo].[get_month_end] (@date datetime)
RETURNS datetime
WITH SCHEMABINDING, RETURNS NULL ON NULL INPUT
AS    
BEGIN
   RETURN dateadd(ms, -3, dateadd (m,datediff(m,0,
          dateadd(m,1,@date)),0))
END
GO

CREATE FUNCTION [dbo].[get_month_start] (@date datetime)
RETURNS datetime
WITH SCHEMABINDING, RETURNS NULL ON NULL INPUT
AS    
BEGIN
   RETURN dateadd(m,datediff(m,0, @date),0)
   END
GO

CREATE FUNCTION [dbo].[get_today_end] (@today datetime)
RETURNS datetime
WITH SCHEMABINDING, RETURNS NULL ON NULL INPUT
AS    
BEGIN
   return dateadd(ms, -3, datediff(d,0,dateadd(d,1,@today)))
END
GO

CREATE FUNCTION [dbo].[get_today_noon](@date datetime)
RETURNS datetime
WITH SCHEMABINDING, RETURNS NULL ON NULL INPUT
AS    BEGIN
   RETURN DATEADD(hh, 12, DATEADD(d,DATEDIFF(d,0, @date),0))
END
GO

CREATE FUNCTION [dbo].[get_today_start] (@today datetime)
RETURNS datetime 
WITH SCHEMABINDING, RETURNS NULL ON NULL INPUT
AS    BEGIN
   return dateadd(day, 0, datediff(d,0,@today))
END
GO

CREATE FUNCTION [dbo].[get_tomorrow_noon](@date datetime)
RETURNS datetime
WITH SCHEMABINDING, RETURNS NULL ON NULL INPUT
AS    BEGIN
   RETURN DATEADD(hh, 12, DATEADD(d,DATEDIFF(d,-1, @date),0))
END
GO

CREATE FUNCTION [dbo].[get_week_end] (@date datetime)
RETURNS datetime
WITH SCHEMABINDING, RETURNS NULL ON NULL INPUT
AS    BEGIN
   return dateadd(yyyy, datepart(yyyy,
      dateadd(weekday,7-datepart(weekday, @date),@date))-1900, 0)
    + dateadd(ms, -3,
      dateadd(dy, datepart(dy,
     dateadd(weekday,7-datepart(weekday, @date),@date)),0) )
END
GO

CREATE FUNCTION [dbo].[get_week_start] (@date datetime)
RETURNS datetime
WITH SCHEMABINDING, RETURNS NULL ON NULL INPUT
AS    BEGIN
   return dateadd(yyyy, datepart(yyyy,
      dateadd(weekday,1-datepart(weekday, @date),@date))-1900, 0)
    + dateadd(dy, datepart(dy,
      dateadd(weekday,1-datepart(weekday, @date),@date))-1,0)
END
GO

CREATE FUNCTION [dbo].[get_weekday_end] (@weekday tinyint,
                                 @date datetime)
RETURNS datetime
WITH SCHEMABINDING, RETURNS NULL ON NULL INPUT
AS    BEGIN
   return dateadd(yyyy, datepart(yyyy,
      dateadd(weekday,@weekday-
      datepart(weekday, @date),@date))-1900, 0)
    + dateadd(ms, -3,
      dateadd(dy, datepart(dy,
      dateadd(weekday,@weekday-datepart(weekday, @date),
                                        @date)),0) )
END
GO

CREATE FUNCTION [dbo].[get_weekday_start] (@weekday tinyint,
                                   @date datetime)
RETURNS datetime
WITH SCHEMABINDING, RETURNS NULL ON NULL INPUT
AS    BEGIN
   return dateadd(yyyy, datepart(yyyy,
      dateadd(weekday,@weekday-
      datepart(weekday, @date),@date))-1900, 0)
    + dateadd(dy, datepart(dy,
      dateadd(weekday,@weekday-datepart(weekday, @date),
                                        @date))-1,0)
END
GO

CREATE FUNCTION [dbo].[get_year_end] (@date datetime)
RETURNS datetime
WITH SCHEMABINDING, RETURNS NULL ON NULL INPUT
AS    BEGIN
RETURN DATEADD(year, DATEDIFF(year, 0, GetDate())+1, 0)-1
END
GO

CREATE FUNCTION [dbo].[get_year_start] (@date datetime)
RETURNS datetime
WITH SCHEMABINDING, RETURNS NULL ON NULL INPUT
AS    BEGIN
   RETURN DATEADD(year,DATEDIFF(year,0, @date),0)
END
GO

CREATE FUNCTION [dbo].[get_yesterday_end] (@today datetime)
RETURNS datetime
WITH SCHEMABINDING, RETURNS NULL ON NULL INPUT
AS    BEGIN
   return dateadd(ms, -3, datediff(d,0,@today))
END
GO

CREATE FUNCTION [dbo].[get_yesterday_start] (@today datetime)
RETURNS datetime
WITH SCHEMABINDING, RETURNS NULL ON NULL INPUT
AS    BEGIN
   RETURN dateadd(day, -1, datediff(d,0,@today))
END
GO

这些对我很有帮助，因为我在日期参数的报告服务中使用了它。您可以简单地创建一个引用此表函数的数据集，然后在RS中的任何日期时间的参数中使用这些数据集。

你可以像这样执行整个表值函数：

SELECT * FROM [MyDB]。[dbo]。[udfCommonDates]（GetDate（））

结果是这样的

enter image description here

对于Reporting Services人员

现在我刚才提到我将这些用于报告服务。 现在RS人们可能在想，但这对我有何帮助，因为我需要一个数据集，而数据集只能基于存储过程或直接表。没问题创建以下存储过程：

CREATE PROCEDURE [dbo].[uspCommonDates] AS
begin
   set datefirst 1
   declare @date datetime
   set @date = getdate()
   select * from dbo.udfCommonDates(@date)
end

现在您已经有一个存储过程用作数据集......现在在报告服务中添加一个新数据集：

enter image description here

现在转到报告的报告参数部分：

enter image description here

现在选择数据集dsFunctions（或你称之为的任何数据集），然后从标量函数中选择任何值字段，例如：

enter image description here

现在，当您运行报告时，它会使用标量：

enter image description here

现在也在您的＆＃34;订阅＆＃34;你会看到＆＃34;使用默认＆＃34;旁边的复选框 日期的参数。如果选中此复选框，它将自动使用默认值 此自定义函数提供的值。它非常灵活，是报告服务的一个非常好的解决方案。这是一个丝网印刷：

enter image description here

答案 1 :(得分：2)

在报表参数配置上（在开发时，而不是在订阅创建时），为参数添加默认值。如果这样做，您将在创建订阅时使用一个名为“使用默认值”的复选框

答案 2 :(得分：1)

我最喜欢处理这种情况的技巧是创建一个名为StartWeek的Integer参数。提示“周开始：”可用值如：

Value    Label
 -4      =dateadd("d",0-weekday(today)+2+(-4*7),today).ToString("m")
 -3      =dateadd("d",0-weekday(today)+2+(-3*7),today).ToString("m")
 -2      =dateadd("d",0-weekday(today)+2+(-2*7),today).ToString("m")
 -1      Previous Week
  0      Current Week
  1      Last Month
  2      This Month

默认值-1。

然后在你的查询中：

DECLARE @StartDate DATETIME
DECLARE @EndDate DATETIME

DECLARE @CurrentDate DATETIME
SET @CurrentDate = GETDATE()
--SET @CurrentDate = 'October 31, 2011'  -- for debugging

IF ( @StartWeek > 0 ) 
   BEGIN
      SET @StartDate = DATEADD(mm, DATEDIFF(mm, 0, @CurrentDate), 0)
      SET @StartDate = DATEADD(mm, 2 - @StartWeek, @StartDate)
      SET @EndDate = DATEADD(s, -1, DATEADD(mm, 1, @StartDate))
   END
ELSE 
   BEGIN
      SET @StartDate = DATEADD(wk,
                               DATEDIFF(wk, 0, DATEADD(d, -1, @CurrentDate))
                               + @StartWeek, 0)
      SET @EndDate = DATEADD(s, -1, DATEADD(day, 7, @StartDate))
   END

Select
   *
FROM
   MyTable
WHERE
   BeginDate <= @EndDate
   AND FinishDate >= @StartDate

答案 3 :(得分：1)

BEGINDATE 

=DateAdd("d", -12, Today())

结束日期

=DateAdd("d", -6, Today())

所以即将于2月10日星期五举行。这会给你一个1/29 - 2/4的日期范围。

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