Python是否有任何数据类型用于FIFO缓冲字符串?我创造了一些东西(下面),但怀疑我正在重新发明轮子。
class Buffer(list):
def __init__(self):
super(Buffer, self).__init__()
def put(self, nlmsg):
for c in nlmsg: self.append(c)
def peek(self, number):
return "".join( [self[i] for i in range(number)] )
def get(self, number):
return "".join( [self.pop(0) for i in range(number)] )
用法示例:
>>> buf = Buffer()
>>> buf.put('abcdefg')
>>> buf
['a', 'b', 'c', 'd', 'e', 'f', 'g']
>>> buf.peek(4)
'abcd'
>>> buf
['a', 'b', 'c', 'd', 'e', 'f', 'g']
>>> buf.get(5)
'abcde'
>>> buf
['f', 'g']
我查看了Queue
但是在添加str时我必须手动拆分每个字节,否则整个str将成为队列中的一个项目。那里有没有这样的东西?
答案 0 :(得分:3)
使用collections.deque
,它将按如下方式实施:
from collections import deque
class Buffer(deque):
def put(self, iterable):
for i in iterable:
self.append(i)
def peek(self, how_many):
return ''.join([self[i] for i in xrange(how_many)])
def get(self, how_many):
return ''.join([self.popleft() for _ in xrange(how_many)])
buf = Buffer()
buf.put('abcdefg')
print buf
print buf.peek(4)
print buf
print buf.get(5)
print buf
示例输出:
deque(['a', 'b', 'c', 'd', 'e', 'f', 'g'])
abcd
deque(['a', 'b', 'c', 'd', 'e', 'f', 'g'])
abcde
deque(['f', 'g'])
答案 1 :(得分:0)
字符串类型本身怎么样?
>>> buf = ""
>>> buf += "abcdefg"
>>> buf
'abcdefg'
>>> list(buf)
['a', 'b', 'c', 'd', 'e', 'f', 'g']
>>> buf[:4] # instead of peek
'abcd'
>>> got,buf = buf[:5],buf[5:] # instead of get
>>> got
'abcde'
>>> buf
'fg'
get()的习语是唯一在这里显得很丑的东西。