Question

//DB connect is here    

foreach ($find as $listing) {

    //bunch of hooblah that discovers $state and $city

    //this and below is all you need to see really
    $city = strip_tags($location_broken3[0]);
    $state = strip_tags($location_broken3[1]);
    print $city; //THIS WORKS...
    print $state; //AS DOES THIS!
    //tried this also
    $city1 = settype($city, 'string');
    $state1 = settype($state, 'string');
    $zip_query = mysql_query("SELECT * FROM zip_codes WHERE city = '$city' 
        AND state = '$state' OR city = '$city' AND full_state = '$state'
    ") or die(mysql_error());
    if ($row = mysql_fetch_array($zip_query)) {
        die("<h1><b>Query Working!!</b></h1>");
    }
}

$zip_query返回零行。如果我将其复制/粘贴到phpmyadmin并将变量替换为相应的字符串，则查询有效。

我在另一个页面上也使用了相同的结构，foreach内的查询（我知道效率不高）具有相同的参数。列名是正确的。快要疯了。你看到错误吗？

更新

为了在这个php页面上测试查询，我尝试了：

$zip_query = mysql_query("SELECT * FROM zip_codes WHERE state = 'california'") or die(mysql_error());

它有效。一些$ state变量='california'。已经尝试了strip_tags和mysql_real_escape_string。

var_dump将返回：

string(10) "California"

查询失败。但如果我手动输入state = 'California'，查询就会起作用。

Answer 1

我猜你在这里省略了括号：

"WHERE city = '$city' AND state = '$state' OR city = '$city' AND full_state = '$state'"

你的意思是：

"WHERE city = '$city' AND state = '$state' OR (city = '$city' AND full_state = '$state')"

这可以简化为：

"WHERE city = '$city' AND (state = '$state' OR full_state = '$state')"

Answer 2

在查询之前尝试在var_dump()和$city上执行$state。

可能是他们是空的或者在他们或其他东西中有引号。

Answer 3

运行时会出现任何错误吗？如果查询错误，必定会出现一些mysql错误。尝试改变一下。

 $zip_query = mysql_query('SELECT * FROM zip_codes WHERE city = \''.$city.'\' AND state = \''.$state.'\'  OR city = \''.$city.'\' AND full_state = \''.$state.'\') ;

还要检查$ city和$ state等是否在数据库中

Answer 4

full_state = '$state)"

什么不见了？：）

Answer 5

我总是喜欢把我的SQL查询放到一个格式中，这样我就可以在调试时记录它或显示它。

$fmt = 'SELECT * FROM zip_codes'
     . ' WHERE ( city = "%1$s" AND state = "%2$s" )'
     . '  OR ( city = "%1$s" AND full_state = "%2$s" )';

$query = sprintf($fmt, $city, $state);
print "<br/>DEBUG: query = <tt>$query</tt><br/>\n";
$result = mysql_query($query);
...

然后，如果您仍然想知道，请在MySQL命令行中测试您的查询（如调试行所示）。

Answer 6

你应该使用mysql_real_escape_string来转义你的值而不是strip_tags：

$city = mysql_real_escape_string($location_broken3[0]);
$state = mysql_real_escape_string($location_broken3[1]);

疯了：Mysql查询不起作用;但很简单

6 个答案: