Question

我正在使用this script来显示文件夹中的随机图片。我有数百个具有重要文件名的图像，所以我正在寻找一种方法来显示每个图像文件名作为图像标题。这可能吗？

这是我使用的脚本：

<?php
/*
By Matt Mullenweg > http://photomatt.net
Inspired by Dan Benjamin > http://hiveware.com/imagerotator.php
Latest version always at:

http://photomatt.net/scripts/randomimage

*/// Make this the relative path to the images, like "../img" or "random/images/".
// If the images are in the same directory, leave it blank.
$folder = '';

// Space seperated list of extensions, you probably won't have to change this.
$exts = 'jpg jpeg png gif';

$files = array(); $i = -1; // Initialize some variables
if ('' == $folder) $folder = './';

$handle = opendir($folder);
$exts = explode(' ', $exts);
while (false !== ($file = readdir($handle))) {
foreach($exts as $ext) { // for each extension check the extension
if (preg_match('/\.'.$ext.'$/i', $file, $test)) { // faster than ereg, case insensitive
$files[] = $file; // it's good
++$i;
}
}
}
closedir($handle); // We're not using it anymore
mt_srand((double)microtime()*1000000); // seed for PHP < 4.2
$rand = mt_rand(0, $i); // $i was incremented as we went along

header('Location: '.$folder.$files[$rand]); // Voila!
?>

Answer 1

如果您只想继续显示单个随机图像，则删除（或注释掉以便以后可以恢复它）标题行，并在文件末尾添加以下行：

//header('Location: '.$folder.$files[$rand]); // Voila!
echo $files[$rand];
?>
<br />
<img src="<?php echo $folder.$files[$rand] ?>" />

您可能需要添加一些CSS样式来设置图像的显示大小，并格式化其上方的标题。

文件名图像为自动标题

1 个答案: