我想在控制台应用程序中绘制时间表：
---------------------------------------------------
| Mo | Tu | We | ... |
---------------------------------------------------
1| Math | | | |
| Teacher | | | |
| Room | | | |
---------------------------------------------------
2| ...
我猜这是一个3D阵列。尺寸1是x，尺寸2是y，尺寸3是称为“课程”的对象。 课程对象的属性是主题，教师，房间和其他（开始，结束，......）
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| Mo | Tu | We | ... |
-------------------------------------------------------------------------
| Math | | | |
| Teacher | | | |
| Room | | | |
| Begin: 2012.1.1 | | | |
-------------------------------------------------------------------------
外观应自动适合行，宽度等。
一个非常酷的解决方案可以是found here
但解决方案只是2D。我做了一些调查，但无法填写完整的对象。
答案 0 :(得分：1)
这不是最漂亮或最优雅的解决方案，也不是最有效的解决方案，但它有效。
假设课程看起来像这样：
class Lesson
{
public string topic = "math";
public string teacher = "mandelbrot";
public string room = "E215";
public string begin = "08:00";
public string end = "09:00";
public Lesson()
: this(null, null, null, null, null)
{
}
public Lesson(string t)
: this(t, null, null, null, null)
{
}
public Lesson(string t, string t2)
: this(t, t2, null, null, null)
{
}
public Lesson(string t, string t2, string r)
: this(t, t2, r, null, null)
{
}
public Lesson(string t, string t2, string r, string b)
: this(t, t2, r, b, null)
{
}
public Lesson(string t, string t2, string r, string b, string e)
{
topic = t??"math";
teacher = t2??"mandelbrot";
room = r??"E215";
begin = b??"08:00";
end = e??"09:00";
}
}
我创建了一个将Lesson[][]数组转换为非常格式化的字符串的类：
class OutPutter
{
private static int[] maxlength = new int[7];
public static Lesson[][] timetable = new Lesson[7][];
public OutPutter()
: this(null)
{
}
public OutPutter(Lesson[][] tt)
{
for (int i = 0; i < 7; i++)
{
maxlength[i] = System.Globalization.CultureInfo.CurrentCulture.DateTimeFormat.DayNames.ElementAt(i).Length;
timetable[i] = ((tt == null || tt[i] == null) ? new Lesson[24] : tt[i]);
}
}
public void add(int day, int hour, Lesson lesson)
{
day -= 1;
timetable[day][hour]=lesson;
int currentLongest = maxlength[day];
if (lesson.begin.Length > currentLongest)
currentLongest = lesson.begin.Length;
if (lesson.end.Length > currentLongest)
currentLongest = lesson.end.Length;
if (lesson.teacher.Length > currentLongest)
currentLongest = lesson.teacher.Length;
if (lesson.topic.Length > currentLongest)
currentLongest = lesson.topic.Length;
if (lesson.room.Length > currentLongest)
currentLongest = lesson.room.Length;
if (currentLongest != maxlength[day])
maxlength[day] = currentLongest;
}
private static Lesson getLesson(int i2, int i)
{
try
{
return timetable[i][i2] ?? new Lesson("", "", "", "", "");
}
catch
{
return new Lesson("", "", "", "", "");
}
}
public override string ToString()
{
StringBuilder sb = new StringBuilder();
int maxLessons = 0;
foreach (Lesson[] current in timetable)
{
if (current.Length > maxLessons)
maxLessons = current.Length;
}
int lineLength = 1;
List<string> formatstrings = new List<string>();
for (int i = 0; i < 7; i++)
{
formatstrings.Add(" {0,"+maxlength[i].ToString()+"}");
sb.Append("|");
sb.AppendFormat(formatstrings.ElementAt(i), System.Globalization.CultureInfo.CurrentCulture.DateTimeFormat.DayNames.ElementAt(i));
lineLength += maxlength[i] + 2;
}
sb.Append("|");
sb.AppendLine();
sb.Append("".PadLeft(lineLength, '='));
for (int i2 = 0; i2 < maxLessons; i2++)
{
sb.AppendLine();
for (int i = 0; i < 7; i++)
{
sb.Append("|");
sb.AppendFormat(formatstrings.ElementAt(i), getLesson(i2, i).topic);
}
sb.Append("|");
sb.AppendLine();
for (int i = 0; i < 7; i++)
{
sb.Append("|");
sb.AppendFormat(formatstrings.ElementAt(i), getLesson(i2, i).teacher);
}
sb.Append("|");
sb.AppendLine();
for (int i = 0; i < 7; i++)
{
sb.Append("|");
sb.AppendFormat(formatstrings.ElementAt(i), getLesson(i2, i).room);
}
sb.Append("|");
sb.AppendLine();
for (int i = 0; i < 7; i++)
{
sb.Append("|");
sb.AppendFormat(formatstrings.ElementAt(i), getLesson(i2, i).begin);
}
sb.Append("|");
sb.AppendLine();
for (int i = 0; i < 7; i++)
{
sb.Append("|");
sb.AppendFormat(formatstrings.ElementAt(i), getLesson(i2, i).end);
}
sb.Append("|");
sb.AppendLine();
sb.Append("".PadLeft(lineLength, '-'));
}
return sb.ToString();
}
}
示例用法：
class Program
{
static void Main(string[] args)
{
OutPutter op = new OutPutter();
op.add(1,1, new Lesson());
op.add(1,3, new Lesson("Analysis"));
op.add(2,5, new Lesson());
op.add(3,0, new Lesson());
op.add(5,7, new Lesson("CompSci", "A. S. Tann."));
Console.Write(op.ToString());
Console.Read();
}
}
就像我说的那样，只是一个快速而肮脏的解决方案，只是为了给你一些如何实现这一点的想法。它绝对不是干净或最佳，所以你应该重构它。 很多。但作为一个例子它应该工作。
修改
这是产生的输出：
| Sunday| Monday| Tuesday| Wednesday| Thursday| Friday| Saturday|
===============================================================================
| | | math| | | | |
| | | mandelbrot| | | | |
| | | E215| | | | |
| | | 08:00| | | | |
| | | 09:00| | | | |
-------------------------------------------------------------------------------
| math| | | | | | |
| mandelbrot| | | | | | |
| E215| | | | | | |
| 08:00| | | | | | |
| 09:00| | | | | | |
-------------------------------------------------------------------------------
| | | | | | | |
| | | | | | | |
| | | | | | | |
| | | | | | | |
| | | | | | | |
-------------------------------------------------------------------------------
| Analysis| | | | | | |
| mandelbrot| | | | | | |
| E215| | | | | | |
| 08:00| | | | | | |
| 09:00| | | | | | |
-------------------------------------------------------------------------------
| | | | | | | |
| | | | | | | |
| | | | | | | |
| | | | | | | |
| | | | | | | |
-------------------------------------------------------------------------------
| | math| | | | | |
| | mandelbrot| | | | | |
| | E215| | | | | |
| | 08:00| | | | | |
| | 09:00| | | | | |
-------------------------------------------------------------------------------
| | | | | | | |
| | | | | | | |
| | | | | | | |
| | | | | | | |
| | | | | | | |
-------------------------------------------------------------------------------
| | | | | CompSci| | |
| | | | | A. S. Tann.| | |
| | | | | E215| | |
| | | | | 08:00| | |
| | | | | 09:00| | |
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