如何对Rabl的藏品进行分页

时间:2012-02-16 15:08:51

标签: ruby-on-rails will-paginate kaminari rabl

我有这个模板:

# app/views/posts/index.rabl
collection @posts => :posts
attributes :id, :title, :subject
child(:user) { attributes :full_name }
node(:read) { |post| post.read_by?(@user) }

女巫回归:

{
    "posts": [
        {
            "post": {
                "id": 5,
                "title": "...",
                "subject": "...",
                "user": {
                    "full_name": "..."
                },
                "read": true
            }
        }
    ]
}

我想添加一些分页参数来呈现这个:

{
    "posts": [
        {
            "post": {
                "id": 5,
                "title": "...",
                "subject": "...",
                "user": {
                    "full_name": "..."
                },
                "read": true
            }
        }
    ],
    "total": 42,
    "total_pages": 12
}

有什么想法吗?非常感谢!

4 个答案:

答案 0 :(得分:16)

对不起我的noob问题,README回答了问题。这是一个分页的例子:

object false

node(:total) {|m| @posts.total_count }
node(:total_pages) {|m| @posts.num_pages }

child(@posts) do
  extends "api/v1/posts/show"
end

注意:我正在使用Kaminari进行分页。

答案 1 :(得分:3)

搜索kaminarirabl时,这是第一个也是非常相关的结果。因此,我想根据生成HAL Specification等链接的this留下解决方案。

首先,从视图开始:

# api/v1/posts/index.rabl
object false

child(@posts) do
  extends 'api/v1/posts/show'
end

node(:_links) do
  paginate @posts
end

然后继续定义分页方法:

# app/helpers/api_helper
module ApiHelper
  def paginate(collection)
    current_page_num = collection.current_page
    last_page_num = collection.total_pages

    {
      :first => first_page,
      :previous => previous_page(current_page_num),
      :self => current_page(current_page_num),
      :next => next_page(current_page_num, last_page_num),
      :last => last_page(last_page_num)
    }
  end

  def first_page
    { :href => url_for(:page => 1) }
  end

  def previous_page(current_page_num)
    return nil if current_page_num <= 1
    { :href => url_for(:page => current_page_num-1) }
  end

  def current_page(current_page_num)
    { :href => url_for(:page => current_page_num) }
  end

  def next_page(current_page_num, last_page_num)
    return nil if current_page_num >= last_page_num
    { :href => url_for(:page => current_page_num+1) }
  end

  def last_page(last_page_num)
    { :href => url_for(:page => last_page_num) }
  end
end

最后,在必要的控制器中包含帮助器。帮助程序可以包含在Api::BaseController中,所有API控制器都从中继承:

helper :api

如果没有Zag zag的解决方案,我无法做到这一点,所以......非常感谢你!

答案 2 :(得分:1)

注意,对于will_paginate 3.0.0,以下工作原理:

node(:total) {|m| @posts.total_entries }
node(:total_pages) {|m| (@posts.total_entries.to_f / @posts.per_page).ceil }
node(:page_num){|m| @posts.current_page}

答案 3 :(得分:0)

这可能就是你要找的;)

object false
node :comments do
  partial('posts/index', object: @posts)
end

node(:pagination) do
  {
    total:@posts.count,
    total_pages: 20
  }
end