Question

我不确定我所遇到的错误的来源究竟是什么，所以请提供更多细节，如果有帮助的话。出于某种原因，当我尝试反序列化我的对象时，不是所有数据都返回（查看文本文件，看起来好像数据都在那里）。

以下是我认为可以解决问题的问题（这个项目有很多代码，所以很多东西都被删除了以便于阅读）：

[Serializable]
public class Unit
{
    public List<ModuleSlot> slotsInFront { get; set; }

    //this would never be reached because the module slot has a customer xml serial object that prevents the normal xml reader from reaching this
    public string some_fake_text{get;set;}
 }

public class ModuleSlot
{
    [XmlIgnore()]
    public StreamShape moduleShape { get; set; }

    [XmlElement("moduleShape")]
    public ShapeSerializer xmlModuleShape
    {
        get
        {
            if (moduleShape == null)
                return null;
            else
            {
                return new ShapeSerializer(moduleShape);
            }
        }
        set
        {
            moduleShape = value.getFirstShape();
        }
    }

}
public class ShapeSerializer : IXmlSerializable
{

    public void ReadXml(System.Xml.XmlReader reader)
    {
        XmlReaderSettings settings = new XmlReaderSettings();
        settings.IgnoreWhitespace = true;
        System.Xml.XmlReader subReader = XmlReader.Create(reader.ReadSubtree(), settings);
        subReader.ReadStartElement();
        while (subReader.Depth > 0)
        {
            xmlStreamShape newXmlShape = new xmlStreamShape();
            newXmlShape = (xmlStreamShape)new XmlSerializer(typeof(xmlStreamShape)).Deserialize(subReader);
            parameters.Add(newXmlShape.getShapeFromSaved());
            subReader.Read();
        }
    }

    public void WriteXml(System.Xml.XmlWriter writer)
    {
        XmlSerializerNamespaces ns = new XmlSerializerNamespaces();
        ns.Add("", "");
        foreach (StreamShape item in parameters)
        {
            xmlStreamShape convertedShape = new xmlStreamShape(item);
            new XmlSerializer(typeof(xmlStreamShape)).Serialize(writer, convertedShape, ns);
        }
    }
}

...

Answer 1

在xml编写器中发现了这个问题。我放弃了形状上的序列化，所以不会在这里发布一个例子，但这里有一个方法有同样的问题但已经解决了（随意发布你用它看到的任何问题）：

public void ReadXml(System.Xml.XmlReader reader)
{
        //Skip whitespaces
        XmlReaderSettings settings = new XmlReaderSettings();
        settings.IgnoreWhitespace = true;
        //Create a reader that will read the list's content
        System.Xml.XmlReader subReader = XmlReader.Create(reader.ReadSubtree(), settings);
        subReader.MoveToContent();
        subReader.ReadStartElement();
        while (subReader.Depth > 0)
        {
            Type type = Type.GetType(this.GetType().Namespace + "." + reader.Name);
            parameters.Add((Port)new XmlSerializer(type).Deserialize(subReader));
        }
        reader.ReadEndElement();
}

Serializer Object C＃中的Serializer

1 个答案: