Question

您好我正在尝试使用-99的输入显示最高和最低数字以打破循环并且不显示-99作为最低数字。任何帮助都会很棒。

int number;
int largeNum = 0 ;
int smallNum = 0;

cout << "enter numbers" ;

do
{
cin >> number;

if ( number > largeNum)
    largeNum = number;

if ( number < largeNum)
    smallNum = number;

if (number < smallNum)
    smallNum = number;

} while (number != -99);



      cout << largeNum << endl;
      cout << smallNum << endl;

Answer 1

你可以这样做：

do {
    cin >> number;

    if ( number == -99 ) {
        break;
    }

    if ( number > largeNum)
        largeNum = number;

    if ( number < largeNum)
        smallNum = number;

    if (number < smallNum)
        smallNum = number;

} while ( true );

Answer 2

问题的更好解决方案是使用排序：

    void main()
    {
    int array[100],n;

    //get number of elements
    cout<<"Enter number of elements: ";
    cin>>n;

    //get elements
    for(int i=0;i<n;i++)
    {
int temp;
    cout<<"Enter element to position "<<i<<" :";
    cin>>temp;
//to break at -99
    if(temp==-99)
    break;
    else
    array[i]=temp;

    }

    //sort the elements in ascending order
    for(int i=0;i<n;i++)
    {
    if(array[i]>array[i+1])
    {
    int temp = array[i];
    array[i] = array[i+1];
    array[i+1] = temp;
    }
    }

    //display smallesst and largest

    cout<<"Smallest: "<<array[0];
    cout<<"Largest: "<<array[n-1];
    }

显示最高和最低输入

2 个答案: