按人气排序

Question

我有'record'表，其中包含两列“meta_value”和“field_id”：

meta_value  field_id    item_id
Customer    11      1
Sweden      1       1
Second      1       1
First       1       1
Done        1       2
No      1       2
First1      2       2
First2      2       2
Finland     2       3
Customer    11      3
112233      2       3
Booked      2       3
First NAme  89      4
Last Name   9       4
Belgium     3       4
Customer Name   11      4
11223344    12      5
Booked      3       5
First Name2 89      5
Last Name2  9       5
The Netherlands 10      6
Customer Name2  11      6
221133      4       6
Booked      4       6

Item_id表示在网站上提交的表单的ID，
field_id - 表格中的参数名称
和meta_value - 此参数的值。

field_id=1是此人的姓名（值存储在meta_value中），field_id=2是关键字（值存储在meta_value中），此人有输入

我需要做的是展示排名前5位的人，他们作为关键词最多次进入“预订” 我在MySQL请求方面不是很好，所以也许有人可以帮助我？

Answer 1

我做到了：

SELECT t3.name, COUNT(*) as Cnt FROM 
(SELECT t1.meta_value AS name, t2.meta_value AS type, t2.item_id AS field_id  FROM 
( SELECT * FROM wp_frm_item_metas WHERE field_id=9) AS t1 INNER JOIN ( SELECT * FROM wp_frm_item_metas WHERE field_id=13) AS t2 ON t1.item_id = t2.item_id WHERE t2.meta_value="Booked") AS t3   GROUP BY t3.name ORDER BY Cnt DESC