Question

我必须找到这两个时间戳之间的区别，请帮助我

27-FEB-12 02.11.31.910000000 AM, 27-FEB-12 02.11.49.002000000 AM

Answer 1

减去它们。结果将是INTERVAL数据类型，在本例中为17.092秒。

SQL> ed
Wrote file afiedt.buf

  1  select to_timestamp( '27-FEB-12 02.11.31.910000000 AM', 'DD-MON-RR HH.MI.SS.FF9 AM') -
  2         to_timestamp( '27-FEB-12 02.11.49.002000000 AM', 'DD-MON-RR HH.MI.SS.FF9 AM')
  3*   from dual
SQL> /

TO_TIMESTAMP('27-FEB-1202.11.31.910000000AM','DD-MON-RRHH.MI.SS.FF9AM')-TO_
---------------------------------------------------------------------------
-000000000 00:00:17.092000000

Answer 2

要更好地控制输出的显示方式，可以使用EXTRACT：

SQL> SELECT TO_CHAR(EXTRACT(HOUR   FROM (x.ts2 - x.ts1)) ,'fm00')                     hours
  2  ,      TO_CHAR(EXTRACT(MINUTE FROM (x.ts2 - x.ts1)) ,'fm00')                     minutes
  3  ,      TO_CHAR(EXTRACT(SECOND FROM (x.ts2 - x.ts1)) ,'fm00.' || RPAD('0',9,'0')) seconds
  4  FROM (SELECT TO_TIMESTAMP('27-FEB-12 02.11.31.910000000 AM', 'DD-MON-RR HH.MI.SS.FF9 AM') ts1
  5        ,      TO_TIMESTAMP('27-FEB-12 02.11.49.002000000 AM', 'DD-MON-RR HH.MI.SS.FF9 AM') ts2
  6        FROM   DUAL) x
  7  ;

HOU MIN SECONDS
--- --- -------------
00  00  17.092000000

SQL>

请参阅http://docs.oracle.com/cd/B28359_01/server.111/b28286/functions052.htm。

如何找到oracle中时间戳的区别？

2 个答案: