Question

我的剃刀视图中有一个链接：

 <a href="Home/Login?ReturnUrl=Disputes/Index"> disputes</a>

在我的登录操作方法中，我使用的是：

 public ActionResult Login(string returnUrl) {
   if (string.IsNullOrEmpty(returnUrl) && Request.UrlReferrer != null)
         returnUrl = Server.UrlEncode(Request.UrlReferrer.PathAndQuery);

   if (Url.IsLocalUrl(returnUrl) && !string.IsNullOrEmpty(returnUrl))
   {
      ViewBag.ReturnURL = returnUrl;
   }

   return View();
 }

在视图中我正在使用它：

 @Html.Hidden("returnUrl",@Request.QueryString)

然后在后期行动方法中：

 public ActionResult LogOn(LogOnModel model, string returnUrl)
 {
   if (ModelState.IsValid)
   {
      if (membershipService.ValidateUser(model.UserName, model.Password, model.Type))
      {
         formsAuthenticationService.SignIn(model.UserName, model.RememberMe);
         SetUserInfo(model.UserName);

         string decodedUrl = "";
         if (!string.IsNullOrEmpty(returnUrl))
            decodedUrl = Server.UrlDecode(returnUrl);

         if (Url.IsLocalUrl(decodedUrl))                    
            return Redirect(decodedUrl);
         else
            return Redirect("Home", Index);

      }
   }
 }

它重定向到：/Disputes/Index但它应该转到myApp/Disputes/Index，其中带有查询字符串的网址就是这样。 /myApp/Home/Login?ReturnUrl=/Disputes/Index

我该如何解决这个问题？

Answer 1

我结合使用上述建议和Request.UrlReferrer来获取之前的位置：

    public ActionResult LogOn(string returnUrl)
    {
        //So that the user can be referred back to where they were when they click logon
        if (string.IsNullOrEmpty(returnUrl) && Request.UrlReferrer != null)
            returnUrl = Server.UrlEncode(Request.UrlReferrer.PathAndQuery);

        if (Url.IsLocalUrl(returnUrl) && !string.IsNullOrEmpty(returnUrl))
        {
            ViewBag.ReturnURL = returnUrl;
        }
        return View();
    }

这样我就不必将位置放在ActionLink。

中

我使用ViewBag.ReturnURL在登录页面中填充隐藏字段。然后在登录HTTPPost ActionResult中，我将用户重定向到隐藏字段中的位置（如果有的话）：

    [HttpPost]
    public ActionResult LogOn(LogOnModel model, string returnUrl)
    {
        //returnURL needs to be decoded
        string decodedUrl = "";
        if (!string.IsNullOrEmpty(returnUrl))
            decodedUrl = Server.UrlDecode(returnUrl);

        //Login logic...

        if (Url.IsLocalUrl(decodedUrl))
        {
            return Redirect(decodedUrl);
        }
        else
        {
            return RedirectToAction("Index", "Home");
        }
    }

Answer 2

在这种情况下，您可以让LogOn操作采用returnUrl参数，如果它不为空，而不是重定向到Home / Index，则可以返回Redirect(returnUrl);。在创建新项目时，请查看VS生成的默认AccountController。它正是如此。

Answer 3

如果ReturnURL为null，请确保从视图中调用操作方法，如下所示：

// FormMethod.post is optional
@using (Html.BeginForm("Login", "Account", new { ReturnUrl = ViewBag.ReturnUrl }, FormMethod.Post))
{
    // login view html
}

帐户管理员：

[AllowAnonymous]
public ActionResult Login(string returnUrl)
{
    ViewBag.ReturnUrl = returnUrl;
    return View();
}

Answer 4

        //Utilities         
        public static ReturnUrl GetReturnUrlValues(string returnUrl)
        {
            //0:Action,1:Controller,2:Area:,3:Id
            ReturnUrl vm = new ReturnUrl();
            using (TBBSEntities context = new TBBSEntities())
            {
                if (returnUrl != null && returnUrl.Length > 10)
                {
                    var counterValue = returnUrl.Split('/');
                    vm.Action = counterValue[0];
                    vm.Controller = counterValue[1];
                    vm.Area = counterValue[2] == "0" ? "" : counterValue[2] ;
                    vm.Id = Convert.ToInt32(counterValue[3]);
                    vm.NullStatus = true;
                    return vm;
                }
                vm.NullStatus = false;
                return vm;
            }
        }

        //Controller
        var transformUrl = Utilities.GetReturnUrlValues(returnUrl);
            if (transformUrl.NullStatus)
            {
            return RedirectToAction(transformUrl.Action, transformUrl.Controller,
                    new { area = transformUrl.Area, id = transformUrl.Id });
            }
            return RedirectToAction("Action", "Controller", new { area = "Area", Id});


        //View
        var returnUrl = "Action/Controller/Area/" + @Model.Id;

登录后重定向返回URL

4 个答案: