Question

从客户端发送的数据不会反序列化。

客户端：

$.ajax({
     type: 'POST',
     dataType: "json",
     url: 'savecommentsservice',
     data: { "Pid": 0, "Comments": [{ "User": "bbbbbb", "Text": "aaaaaaaa" }, { "User": "ddddddd", "Text": "ccccccccc"}] },

DTO：

public class Comment
{
    public string User { get; set; }
    public string Text { get; set; }
}
public class SaveCommentsRequest
{
    public int Pid { get; set; }
    public string SiteId { get; set; }
    public string Column { get; set; }
    public List<Comment> Comments { get; set; }
}

服务器：

Routes.Add<SaveCommentsRequest>("/savecommentsservice");

...

public object Execute(SaveCommentsRequest request)
    {
        // Why is request.Comments null !!! All other params of the request works fine

        // THe string I'm putting in is generated below - just to make sure its correct
        request.Comments = new List<Comment>();
        request.Comments.Add(new Comment { Text = "aaaaaaaa", User = "bbbbbb" });
        request.Comments.Add(new Comment { Text = "ccccccccc", User = "ddddddd" });

        var thisIsWhatIPutInto$AjaxCall = JsonSerializer.SerializeToString<SaveCommentsRequest>(request);

任何想法有什么不对？为什么没有填充Comments数组。正如您从注释中看到的那样，我使用servicestack json序列化程序生成了字符串。

也许我在这里错过了一些观察？

修改当看到小提琴发射的时候，我看到了这个：

    POST http://localhost:4920/savecommentsservice HTTP/1.1
Host: localhost:4920
User-Agent: Mozilla/5.0 (Windows NT 5.1; rv:10.0.2) Gecko/20100101 Firefox/10.0.2
Accept: application/json, text/javascript, */*; q=0.01
Accept-Language: zh,en-us;q=0.7,en;q=0.3
Accept-Encoding: gzip, deflate
Connection: keep-alive
Content-Type: application/x-www-form-urlencoded; charset=UTF-8
X-Requested-With: XMLHttpRequest
Referer: http://localhost:4920/default.cshtml?viewId=3
Content-Length: 227
Cookie: ASP.NET_SessionId=slbw453revfgmwuuxyrim1an
Pragma: no-cache
Cache-Control: no-cache

SiteId=Site1&Pid=0&Column=C6&Comments%5B0%5D%5BUser%5D=bbbbbb&Comments%5B0%5D%5BText%5D=aaaaaaaa&Comments%5B1%5D%5BUser%5D=ddddddd&Comments%5B1%5D%5BText%5D=ccccccccc&Comments%5B2%5D%5BUser%5D=ggggggg&Comments%5B2%5D%5BText%5D=

在萤火虫中：

    Parametersapplication/x-www-form-urlencoded
Column  C6
Comments[0][Text]   aaaaaaaa
Comments[0][User]   bbbbbb
Comments[1][Text]   ccccccccc
Comments[1][User]   ddddddd
Comments[2][Text]   
Comments[2][User]   ggggggg
Pid 0
SiteId  SiteId0
Source
SiteId=SiteId0&Pid=0&Column=C6&Comments%5B0%5D%5BUser%5D=bbbbbb&Comments%5B0%5D%5BText%5D=aaaaaaaa&Comments%5B1%5D%5BUser%5D=ddddddd&Comments%5B1%5D%5BText%5D=ccccccccc&Comments%5B2%5D%5BUser%5D=ggggggg&Comments%5B2%5D%5BText%5D=

此致

Larsi

Answer 1

正如您在默认情况下所看到的，jQuery的Ajax将其提交为“application / x-www-form-urlencoded”，这是默认的HTML Form Post Content-Type。不幸的是，它不能很好地处理嵌套对象，ServiceStack会期望JSV Format中的嵌套对象。

因此，对于复杂类型/嵌套对象，您希望告诉jQuery将请求作为JSON发送，您可以通过指定 contentType：application / json 参数来执行此操作，例如：

var data = { "Pid": 0, "Comments": [{ "User": "bbbbbb", "Text": "aaaaaaaa" }]};
$.ajax({
     type: 'POST',
     dataType: "json",
     contentType: "application/json",
     url: 'savecommentsservice',
     data: JSON.stringify(data)
);

Answer 2

我相信你需要在你的字符串中添加参数（request）的名称。有点像..

$.ajax({
     type: 'POST',
     dataType: "json",
     url: 'savecommentsservice',
     data: {"request": "Pid": 0, "Comments": [{ "User": "bbbbbb", "Text": "aaaaaaaa" }, { "User": "ddddddd", "Text": "ccccccccc"}] },

无法反序列化数组

2 个答案: