我的主线程中有一些自定义信号,我想在其他线程中发出,但我不知道如何连接它们。有人可以发一个例子吗?
例如:
import sys, time
from PyQt4 import QtGui as qt
from PyQt4 import QtCore as qtcore
app = qt.QApplication(sys.argv)
class widget(qt.QWidget):
signal = qtcore.pyqtSignal(str)
def __init__(self, parent=None):
qt.QWidget.__init__(self)
self.signal.connect(self.testfunc)
def appinit(self):
thread = worker()
thread.start()
def testfunc(self, sigstr):
print sigstr
class worker(qtcore.QThread):
def __init__(self):
qtcore.QThread.__init__(self, parent=app)
def run(self):
time.sleep(5)
print "in thread"
self.emit(qtcore.SIGNAL("signal"),"hi from thread")
def main():
w = widget()
w.show()
qtcore.QTimer.singleShot(0, w.appinit)
sys.exit(app.exec_())
main()
信号从未上升过。
答案 0 :(得分:5)
您实际上是将错误的信号连接到插槽。一些修改使其按预期运行
import sys, time
from PyQt4 import QtGui as qt
from PyQt4 import QtCore as qtcore
app = qt.QApplication(sys.argv)
class widget(qt.QWidget):
def __init__(self, parent=None):
qt.QWidget.__init__(self)
def appinit(self):
thread = worker()
self.connect(thread, thread.signal, self.testfunc)
thread.start()
def testfunc(self, sigstr):
print sigstr
class worker(qtcore.QThread):
def __init__(self):
qtcore.QThread.__init__(self, parent=app)
self.signal = qtcore.SIGNAL("signal")
def run(self):
time.sleep(5)
print "in thread"
self.emit(self.signal, "hi from thread")
def main():
w = widget()
w.show()
qtcore.QTimer.singleShot(0, w.appinit)
sys.exit(app.exec_())
main()