避免结果中包含空值的行

Question

我在执行查询时得到了结果：

state city  user_count   restaurant_count   order_count
a      b      0            0                 5
a      c      2            0                 0 
a      d      0            0                 0

我的查询是：

SELECT `eat_state_locale`.`state`, `eat_city_locale`.`city`, `eat_city_locale`.`location`, `eat_city`.`city_id`, count(distinct eat_user.user_id) as user_count, count(distinct eat_delivery.restaurant_id) as restaurant_count, count(distinct eat_order.order_id) as order_count FROM (`eat_state`) JOIN `eat_state_locale` ON `eat_state_locale`.`state_id`=`eat_state`.`state_id` JOIN `eat_city` ON `eat_state`.`state_id`=`eat_city`.`state_id` JOIN `eat_city_locale` ON `eat_city_locale`.`city_id`=`eat_city`.`city_id` LEFT JOIN `eat_user` ON `eat_user`.`city_id`=`eat_city`.`city_id` LEFT JOIN `eat_delivery` ON `eat_delivery`.`delivery_city_id`=`eat_city`.`city_id` LEFT JOIN `eat_order` ON `eat_order`.`delivery_city_id`=`eat_city`.`city_id` LEFT JOIN `eat_printer` ON `eat_printer`.`order_id`=`eat_order`.`order_id` WHERE `eat_state_locale`.`language_id` = 1 AND `eat_city_locale`.`language_id` = 1 GROUP BY `eat_city`.`city_id` ORDER BY `eat_state`.`state_id` asc 

这里我需要获得结果（在避免空值之后：）

state city  user_count   restaurant_count   order_count
a      b      0            0                 5
a      c      2            0                 0 

我将如何得到这样的结果？这里的计数结果没有问题。我需要避免空结果

Answer 1

修改

SELECT 
   blah
HAVING
   user_count > 0 AND
   restaurant_count > 0 
   AND order_count > 0;

Answer 2

WHERE .... AND ( user_count != 0 OR restaurant_count != 0 OR  order_count  != 0 )

如果不起作用，请尝试：

GROUP BY .... HAVING user_count > 0 OR restaurant_count > 0 OR  order_count  > 0

Answer 3

尝试在哪里条件

AND your_field IS NOT NULL