Question

我使用的是使用ApplicationContext加载到我的Java应用程序中的XML配置文件。

XML配置文件通过使用PropertyPlaceholderConfigurer从多个属性文件中读取来解析其属性。

我想让每个属性文件都是可选的。我认为这是通过将ignoreUnresolsvablePlaceholders设置为true来完成的，但是当我运行应用程序时出现以下异常（db-default.properties存在但db.properties不存在）：

Exception in thread "main" org.springframework.beans.factory.BeanInitializationException: Could not load properties; nested exception is java.io.FileNotFoundException: class path resource [db.properties] cannot be opened because it does not exist

这就是我的XML配置：

<?xml version="1.0" encoding="UTF-8"?>

<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:context="http://www.springframework.org/schema/context"
xsi:schemaLocation="http://www.springframework.org/schema/beans
    http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
    http://www.springframework.org/schema/context
    http://www.springframework.org/schema/context/spring-context-3.0.xsd">

    <bean id="placeholder-configurer-1" class="org.springframework.beans.factory.config.PropertyPlaceholderConfigurer">
        <property name="order" value="1"/>
        <property name="ignoreUnresolvablePlaceholders" value="true"/>
    </bean>   

    <bean id="placeholder-configurer-2" class="org.springframework.beans.factory.config.PropertyPlaceholderConfigurer">
        <property name="order" value="2"/>
        <property name="ignoreUnresolvablePlaceholders" value="true"/>
        <property name="location" value="classpath:/db-default.properties"/>
    </bean>   

    <bean id="placeholder-configurer-3" class="org.springframework.beans.factory.config.PropertyPlaceholderConfigurer">
        <property name="order" value="3"/>
        <property name="ignoreUnresolvablePlaceholders" value="true"/>
        <property name="locations">
            <list>
                <value>classpath:/db.properties</value>
            </list>
        </property>
    </bean>

    <bean id="MyDataSource" class="org.apache.commons.dbcp.BasicDataSource" destroy-method="close">
        <property name="driverClassName" value="${jdbc.driver}"/>
        <property name="url" value="${jdbc.url}"/>
        <property name="username" value="${jdbc.username}"/>
        <property name="password" value="${jdbc.password}"/>
    </bean>

</beans>

如何使db.properties成为可选属性文件？

Answer 1

<property name="ignoreResourceNotFound" value="true"/>

Answer 2

这也应该有效：

<context:property-placeholder ignore-resource-not-found="true" location="classpath:your.properties" ... />

如何在Spring配置文件中使用可选属性文件？

2 个答案: