Question

我一直在为方法

中设置的错误数组收到此错误

这是代码

public function showerrors() {
        echo "<h3> ERRORS!!</h3>";
        foreach ($this->errors as $key => $value)
        {
            echo $value;
        }
    }

当我运行程序时，我一直得到这个“警告：为foreach（）提供的参数无效” 我在构造函数中设置了错误数组，如下所示

 $this->errors = array();

所以我不完全确定为什么它不会打印错误！

public function validdata() {
        if (!isset($this->email)) {
            $this->errors[] = "email address is empty and is a required field";
        }

        if ($this->password1 !== $this->password2) {
            $this->errors[] = "passwords are not equal ";
        }
        if (!isset($this->password1) || !isset($this->password2)) {
            $this->errors[] = "password fields cannot be empty ";
        }
        if (!isset($this->firstname)) {
            $this->errors[] = "firstname field is empty and is a required field";
        }
        if (!isset($this->secondname)) {
            $this->errors[] = "second name field is empty and is a required field";
        }

        if (!isset($this->city)) {
            $this->errors[] = "city field is empty and is a required field";
        }


        return count($this->errors) ? 0 : 1;
    }

这是我如何向数组本身添加数据！谢谢你的帮助！

好吧，我把它添加到方法

public function showerrors() {
        echo "<h3> ERRORS!!</h3>";
        echo "<p>" . var_dump($this->errors) . "</p>";
        foreach ($this->errors as $key => $value)
        {
            echo $value;
        }

然后它在我的页面上输出

错误！ string（20）“无效提交!!”如果我在我的文本框中没有输入任何内容，那么就说它是一个字符串??

这里也是我的构造函数，关于这个我对php的新内容！

  public function __construct() {

        $this->submit  = isset($_GET['submit'])? 1 : 0;
        $this->errors = array();
        $this->firstname = $this->filter($_GET['firstname']);
        $this->secondname = $this->filter($_GET['surname']);
        $this->email = $this->filter($_GET['email']);
        $this->password1 = $this->filter($_GET['password']);
        $this->password2 = $this->filter($_GET['renter']);
        $this->address1 = $this->filter($_GET['address1']);
        $this->address2 = $this->filter($_GET['address2']);

        $this->city = $this->filter($_GET['city']);
        $this->country = $this->filter($_GET['country']);
        $this->postcode = $this->filter($_GET['postcode']);


        $this->token = $_GET['token'];
    }

Answer 1

在您的表单上默认（没有填写）验证，其中设置了消息"invalid submission"，您遗漏了括号[]，导致$this->errors被普通字符串覆盖而不是附加到数组。

// Change
$this->errors = "invalid submission";

//...to...
$this->errors[] = "invalid submission";

foreach（）错误警告：为foreach（）提供的参数无效

1 个答案: